How to subclass file

[Yves Dorfsman]

I want to create a subclass of 'file' but need to open the file with os.open
(because I want to open it in exclusive mode), and need an additional method.

Because I need an additional method, I truly need a object of my sublass.
If I do something like

class myFile(file):

def __new__(cls, filename):
import os
fd = os.open(filename, os.O_WRONLY | os.O_CREAT | os.O_EXCL)

return os.fdoen(fd, 'w')

def myMethod(self):
do_something
then x = myFile('somefilename') is of type file, not myFile, and therefore
does not have myMethod as a valid method.

Now if I try:

class myFile(file):

def __new__(cls, filename):
import os
fd = os.open(filename, os.O_WRONLY | os.O_CREAT | os.O_EXCL)

obj = file.__new__(cls)

return obj

def myMethod(self):
do_something

Then it fails, because the 'file' constructor needs a filename. I can provide
the filename, but it will then try to re-open that file, and even if I did
manage to create an object file, how do I connect the file descriptor created
by os.open to my object ?
Thanks.
Yves.
http://www.SollerS.ca

[Gabriel Genellina]

En Wed, 14 May 2008 21:23:26 -0300, Yves Dorfsman <yv**@zioup.com>
escribió:

I want to create a subclass of 'file' but need to open the file with
os.open
(because I want to open it in exclusive mode), and need an additional
method.

Because I need an additional method, I truly need a object of my sublass.
If I do something like

class myFile(file):

def __new__(cls, filename):
import os
fd = os.open(filename, os.O_WRONLY | os.O_CREAT | os.O_EXCL)
return os.fdoen(fd, 'w')

def myMethod(self):
do_something
then x = myFile('somefilename') is of type file, not myFile, and
therefore
does not have myMethod as a valid method.

Use delegation instead of inheritance.

from __future__ import with_statement
import os

class myFile(object):
__slots__ = ['_file']

def __init__(self, filename):
fd = os.open(filename, os.O_WRONLY | os.O_CREAT | os.O_EXCL)
f = os.fdopen(fd, 'w')
object.__setattr__(self, '_file', f)

def __getattr__(self, name):
return getattr(self._file, name)

def __setattr__(self, name, value):
setattr(self._file, name, value)

def mymethod(self):
print "anything"
<output>
pyregular_file = open(r"c:\\temp\\regular.txt", "wt")
pyspecial_file = myFile(r"c:\\temp\\special.txt")
pyprint regular_file
<open file 'c:\\temp\\regular.txt', mode 'wt' at 0x00A411D0>
pyprint special_file
<__main__.myFile object at 0x00A3D1D0>
pyprint dir(regular_file)
['__class__', '__delattr__', '__doc__', '__enter__', '__exit__',
'__getattribute
__', '__hash__', '__init__', '__iter__', '__new__', '__reduce__',
'__reduce_ex__
', '__repr__', '__setattr__', '__str__', 'close', 'closed', 'encoding',
'fileno'
, 'flush', 'isatty', 'mode', 'name', 'newlines', 'next', 'read',
'readinto', 're
adline', 'readlines', 'seek', 'softspace', 'tell', 'truncate', 'write',
'writeli
nes', 'xreadlines']
pyprint dir(special_file)
['__class__', '__delattr__', '__doc__', '__getattr__', '__getattribute__',
'__ha
sh__', '__init__', '__module__', '__new__', '__reduce__', '__reduce_ex__',
'__re
pr__', '__setattr__', '__slots__', '__str__', '_file', 'mymethod']
pywith special_file:
.... special_file.write("hello\n")
.... special_file.mymethod()
....
anything
pyprint "closed?", special_file.closed
closed? True
</output>

(note that __enter__/__exit__ -used by the with statement- work fine, even
if not listed by dir(); also the "closed" attribute exists and is set
correctly)

Note also that myFile is *not* a subclass of file:

pyisinstance(special_file, file)
False

but it has all methods and attributes of file objects, even if
dir(special_files) doesn't list them. Duck typing in action - typical
Python code should work fine with this myFile object instead of a true
file object, but if you actually need a file subclass, I think you'll have
to write a C extension.

--
Gabriel Genellina