learning with python question (HtTLaPP)

[umpsumps]

Hello all,

I've been trying to teach myself python from "How to Think Like a
Python Programmer" and have been trying to write a script that checks
'words.txt' for parameters (letters) given. The problem that is the i
can only get results for the exact sequnce of parameter 'letters'.
I'll spare posting all the different ways I've tried to search for
specific letters. But they are all generally:

for line in fin:
for linechar in line:
for ch in letters:

or the "for linechar in line:" and "for ch in letters:" get switched..
I'm getting really frustrated to say the least.

What alternative method could I use that isn't too advanced? Any
tips/suggestions on the code itself would be greatly appreciated, and
tips for learning in general.

here is the code that returns a certain sequence:

>>def searchtxt(letters):

fin = open('words.txt')
words = ""
index = 0
count = 0
for line in fin:
index +=1
if letters in line.strip():
count += 1
words = line.strip() + '\n' + words

print words
print index, 'lines searched..', count, letters, 'words present'

Thank you in advance.

[Eric Wertman]

Python Programmer" and have been trying to write a script that checks

'words.txt' for parameters (letters) given. The problem that is the i
can only get results for the exact sequence of parameter 'letters'.

The "re" module comes to mind:

text = open('words.txt','r').read()
letters = 'sequence'
results = re.findall(letters,text)

result_count = len(results)

# one word per line:
for result in results :
print result

# one line
print ' '.join(results)

of course, you may need to invest a little time in regular expression
syntax to get exactly what you want, but I think you'll find that's
not wasted effort, as this is pretty standard and used in a lot of
other places.

[umpsumps]

Eric,

Thank you for helping.

Is the way I wrote the function inherently wrong? What I wrote
returns the sequence, however I'm trying to make the output match for
the letters in the string entered, not necessarily the string
sequence. For example if I search words.txt with my function for
'uzi' I get this:

>>searchtxt('uzi')

gauziest
gauzier
fuzing
fuzils
fuzil
frouziest
frouzier
defuzing

113809 lines searched.. 8 uzi words present
Only the sequence shows up 'uzi'. I don't get words like 'unzip' or
'Zurich' . I've only barely started on invocation and maybe writing
something like I'm describing is above what level I'm currently at.


On Apr 26, 2:20*pm, "Eric Wertman" <[e-mail]:

*Python Programmer" and have been trying to write a script that checks
*'words.txt' for parameters (letters) given. *The problem that is the i
*can only get results for the exact sequence of parameter 'letters'.

The "re" module comes to mind:

text = open('words.txt','r').read()
letters = 'sequence'
results = re.findall(letters,text)

result_count = len(results)

# one word per line:
for result in results :
* * print result

# one line
print ' '.join(results)

of course, you may need to invest a little time in regular expression
syntax to get exactly what you want, but I think you'll find that's
not wasted effort, as this is pretty standard and used in a lot of
other places.

[Eric Wertman]

On Sat, Apr 26, 2008 at 7:50 PM, <um******@gmail.comwrote:

ok.. I finally made something that works.. Please let me know what you
think:

>>def lines(letters):

fin = open('words.txt')
count = 0
rescount = 0 # count the number of results
results = "" # there are words that contain the letters
for line in fin:
needs = 0
x = str(line.strip())
for ch in letters:
if ch not in x:
pass
else:
needs = needs + 1
if needs == len(letters):
rescount += 1
results = results + '\n' + x
count += 1
print count, 'lines searched'
print results, '\n'
print 'result count is: ', rescount

That's pretty much it.. I'm guessing you are assuming your file has
one word per line? I took a shot at it, without using the regex
module:

file = open('spyware')

my_string = 'uzi'
length = len(my_string)
words = []

for line in file :
chunks = line.strip().split()
for chunk in chunks :
x = 0
for char in my_string :
x = chunk.rfind(char,x)
if x 0 :
words.append(chunk)

print '\n'.join(words)
or with the re module:

import re

text = open('words.txt').read()
pattern = '\S*u\S*z\S*i\S*'
stuff = re.findall(pattern,text)
count = len(stuff)

print "Found %d words :" % (count)
print "\n".join(stuff)

[Gabriel Genellina]

En Sat, 26 Apr 2008 20:50:57 -0300, <um******@gmail.comescribió:

ok.. I finally made something that works.. Please let me know what you
think:

>>>def lines(letters):

fin = open('words.txt')
count = 0
rescount = 0 # count the number of results
results = "" # there are words that contain the letters
for line in fin:
needs = 0
x = str(line.strip())
for ch in letters:
if ch not in x:
pass
else:
needs = needs + 1
if needs == len(letters):
rescount += 1
results = results + '\n' + x
count += 1
print count, 'lines searched'
print results, '\n'
print 'result count is: ', rescount

That's pretty good. Some improvements:

- The "natural" way to collect the results is using a list, appending words to it. Later you can print it one word per line or in any other format you want. Also, we don't need the "rescount" variable: it's just the length of the list.

needs = 0
for ch in letters:
if ch not in x:
pass
else:
needs = needs + 1
if needs == len(letters):

The overall idea is to test whether ALL letters are in the word `x`, ok? So as soon as we find a letter that isn't in the word, we are sure the test failed and we can break out of the loop. And if we get up to the last step, that means that all the letters were in the word (else we would not have got so far). So we don't have to count the letters; instead, we can use the "else" clause of the for loop (it means "the loop was exhausted completely".)

- I don't like the names "x" nor "ch"; I'm using "word" and "letter" instead. This is the revised version:

def lines(letters):
fin = open('words.txt')
count = 0
results = [] # there are words that contain the letters
for line in fin:
word = line.strip()
for letter in letters:
if letter not in x:
break
else:
results.append(word)
count += 1
print count, 'lines searched'
print '\n'.join(results), '\n'
print 'result count is: ', len(results)

That "\n".join(...) means "concatenate all the items in the list using \n as a separator between items" and it's a pretty common idiom in Python.

--
Gabriel Genellina