Curious relation

[Greg J]

I was reading the programming Reddit tonight and came across this
(http://reddit.com/info/6gwk1/comments/):

>>([1]>2)==True

True

>>[1]>(2==True)

True

>>[1]>2==True

False

Odd, no?

So, can anyone here shed light on this one?

[Dan Bishop]

On Apr 23, 11:51 pm, Greg J <[e-mail]:

I was reading the programming Reddit tonight and came across this
(http://reddit.com/info/6gwk1/comments/):

>([1]>2)==True

True

>[1]>(2==True)

True

>[1]>2==True

False

Odd, no?

So, can anyone here shed light on this one?

A long time ago, it wasn't possible for comparison operators to raise
exceptions, so it was arbitrarily decided that numbers are less than
strings. Thus, [1]>2 and [1]>False. This explains your first two
examples.

For the third, remember that the comparison operators are chained, so
a>b==c means (a>b) and (b==c). Since 2==True is false, so is the
entire expression.

In Python 3.0, all three of these expressions will raise a TypeError.

[Greg J]

On Apr 24, 12:08 am, Dan Bishop <[e-mail]:

On Apr 23, 11:51 pm, Greg J <[e-mail]:

I was reading the programming Reddit tonight and came across this
(http://reddit.com/info/6gwk1/comments/):

>>([1]>2)==True

True

>>[1]>(2==True)

True

>>[1]>2==True

False

Odd, no?

So, can anyone here shed light on this one?

A long time ago, it wasn't possible for comparison operators to raise
exceptions, so it was arbitrarily decided that numbers are less than
strings. Thus, [1]>2 and [1]>False. This explains your first two
examples.

Sure, those I understood.

For the third, remember that the comparison operators are chained, so
a>b==c means (a>b) and (b==c). Since 2==True is false, so is the
entire expression.

Ach! Of course. For some reason I was blanking on the chained nature
of relational operators in Python.

Thanks for the reminder!

>
In Python 3.0, all three of these expressions will raise a TypeError.