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Re: Partition list with predicate


"Jared Grubb" <ja*********@gmail.comwrote in message
news:92******************************************@ mail.gmail.com...
| I want a function that removes values from a list if a predicate
evaluates
| to True.

Forget the rigamarole you posted, which has several defects.
If you must modify the list in place, because you have multiple references
to it:

lst[:] = filter(lambda x: not pred(x), lst)

Otherwise, just lst = filter(....)

tjr

Jun 27 '08 #1
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