problem with sorting

[ankitks.mital]

>>dict = {'M':3, 'R':0, 'S':2}

>>print dict

{'S': 2, 'R': 0, 'M': 3}

now if I wanted sorted values in list, i am not able to do this

>>print dict.values().sort()

None

it returns None instead of [0, 2, 3]

[Paddy]

On Mar 28, 5:38 am, [e-mail] wrote:

>dict = {'M':3, 'R':0, 'S':2}
print dict

{'S': 2, 'R': 0, 'M': 3}

now if I wanted sorted values in list, i am not able to do this>>print dict.values().sort()

None

it returns None instead of [0, 2, 3]

Try:

from pprint import pprint as pp
pp(my_dict)
It works well for other built-in types too.

P.S it is not good to use a name, dict, that already has a use in
Python.

- Paddy.

[jwelby]

On Mar 28, 5:38 am, [e-mail] wrote:

>dict = {'M':3, 'R':0, 'S':2}
print dict

{'S': 2, 'R': 0, 'M': 3}

now if I wanted sorted values in list, i am not able to do this>>print dict.values().sort()

None

it returns None instead of [0, 2, 3]

The sort method works by sorting 'in place'. That means it doesn't
return the sorted value, but just sorts the sequence.

>>t = {'M':3, 'R':0, 'S':2}
x = t.values()
x.sort()
x

[0, 2, 3]

or you can use sorted(), which does return the sorted sequence:

>>sorted(t.values())

[0, 2, 3]

[raj]

To ankit:

Well, sort() doesn't return the sorted list. It returns None. Why not
this straightforward way?
dvals = dict.values()
dvals.sort()
print dvals

[Duncan Booth]

ca********@gmail.com wrote:

On Mar 28, 1:57ÿam, raj <[e-mail]:

>To ankit:

Well, sort() doesn't return the sorted list. It returns None. Why not
this straightforward way?
dvals = dict.values()
dvals.sort()
print dvals

Why not sorted( dict.values() ).

If you are going to do it that way then it may be preferable to use
itervalues:

print sorted(dict.itervalues())

Both this and raj's suggestion create a single sorted list. Your suggestion
creates two lists: the unsorted one and a separate sorted one. In most
cases the difference is probably insignificant, but if you have a *lot* of
values it might make a difference.

[bearophileHUGS]

Duncan Booth:

Both this and raj's suggestion create a single sorted list. Your suggestion
creates two lists: the unsorted one and a separate sorted one. In most
cases the difference is probably insignificant, but if you have a *lot* of
values it might make a difference.

The good thing of Python 3.0 is that it forces you to do the right
thing here :-)

Bye,
bearophile