How to subtract/add from/to a value found using the RE module?

nihilium

The beginning of the script goes like this.

Now I want to subtract 1 from as well as add 1 to which always has a numerical value.

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Another thing I don't get how to implement in regex, is how to match ranges such as 2001-3000. I tried using the following, which apparently did not work:

Mar 22 '08 #1

bvdet

The beginning of the script goes like this.

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1. import urllib2
2. request = urllib2.urlopen('http://ssd.jpl.nasa.gov/sbdb.cgi?sstr=2000')
3. source= request.read()
4. import re
5. name = re.compile(r'size=\"\+1\"\>\<b\>(\d+) (\w+)')
6. thename = name.search(source)

Now I want to subtract 1 from as well as add 1 to

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1. thename.group(1)

which always has a numerical value.

----

Another thing I don't get how to implement in regex, is how to match ranges such as 2001-3000. I tried using the following, which apparently did not work:

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1. list = re.compile(r'size=\"\+1\"\>\<b\>[2001-3000] \w+')

This pattern will match a number in the range 2001-3000:

Mar 22 '08 #2

nihilium

This pattern will match a number in the range 2001-3000:

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1. re.compile(r'size=\"\+1\"\>\<b\>(200[1-9]|2[1-9][0-9][0-9]|3000) (\w+)')

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1. source = source.replace(thename.group(1),str(int(thename.group(1))+1))
2.  
3. patt = re.compile(r'size=\"\+1\"\>\<b\>(200[1-9]|2[1-9][0-9][0-9]|3000) (\w+)')
4. m = patt.search(source)
5. print m.group(1)

That works, thanks again. The range should look like this, though:

as your solution did not match the range 2010-2099.

Mar 24 '08 #3

bvdet

That works, thanks again. The range should look like this, though:

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1.  
2. re.compile(r'size=\"\+1\"\>\<b\>(2[0-9][0-9][1-9]|2[1-9][0-9][0-9]|2[0-9][1-9][0-9]|3000) \w+')
3.  

as your solution did not match the range 2010-2099.

Oops! Thanks for posting back and the correction.

Mar 24 '08 #4