How to subtract/add from/to a value found using the RE module?

[nihilium]

The beginning of the script goes like this.

import urllib2
request = urllib2.urlopen('http://ssd.jpl.nasa.gov/sbdb.cgi?sstr=2000')
source= request.read()
import re
name = re.compile(r'size=\"\+1\"\>\<b\>(\d+) (\w+)')
thename = name.search(source)

Now I want to subtract 1 from as well as add 1 to

thename.group(1)

which always has a numerical value.

----

Another thing I don't get how to implement in regex, is how to match ranges such as 2001-3000. I tried using the following, which apparently did not work:

list = re.compile(r'size=\"\+1\"\>\<b\>[2001-3000] \w+')

[bvdet]

The beginning of the script goes like this.

import urllib2
request = urllib2.urlopen('http://ssd.jpl.nasa.gov/sbdb.cgi?sstr=2000')
source= request.read()
import re
name = re.compile(r'size=\"\+1\"\>\<b\>(\d+) (\w+)')
thename = name.search(source)

Now I want to subtract 1 from as well as add 1 to

thename.group(1)

which always has a numerical value.

----

Another thing I don't get how to implement in regex, is how to match ranges such as 2001-3000. I tried using the following, which apparently did not work:

list = re.compile(r'size=\"\+1\"\>\<b\>[2001-3000] \w+')

This pattern will match a number in the range 2001-3000:

re.compile(r'size=\"\+1\"\>\<b\>(200[1-9]|2[1-9][0-9][0-9]|3000) (\w+)')

source = source.replace(thename.group(1),str(int(thename.group(1))+1))
 
patt = re.compile(r'size=\"\+1\"\>\<b\>(200[1-9]|2[1-9][0-9][0-9]|3000) (\w+)')
m = patt.search(source)
print m.group(1)

[nihilium]

This pattern will match a number in the range 2001-3000:

re.compile(r'size=\"\+1\"\>\<b\>(200[1-9]|2[1-9][0-9][0-9]|3000) (\w+)')

source = source.replace(thename.group(1),str(int(thename.group(1))+1))
 
patt = re.compile(r'size=\"\+1\"\>\<b\>(200[1-9]|2[1-9][0-9][0-9]|3000) (\w+)')
m = patt.search(source)
print m.group(1)

That works, thanks again. The range should look like this, though:

 
re.compile(r'size=\"\+1\"\>\<b\>(2[0-9][0-9][1-9]|2[1-9][0-9][0-9]|2[0-9][1-9][0-9]|3000) \w+')
 

as your solution did not match the range 2010-2099.

[bvdet]

That works, thanks again. The range should look like this, though:

 
re.compile(r'size=\"\+1\"\>\<b\>(2[0-9][0-9][1-9]|2[1-9][0-9][0-9]|2[0-9][1-9][0-9]|3000) \w+')
 

as your solution did not match the range 2010-2099.

Oops! Thanks for posting back and the correction.