Convert int to float

[Guido van Brakel]

Hello

I have this now:

def gem(a):
g = sum(a) / len(a)
return g

print gem([1,2,3,4])
print gem([1,10,100,1000])
print gem([1,-2,3,-4,5])

It now gives a int, but i would like to see floats. How can integrate
that into the function?

Regards,

--
Guido van Brakel
Life is like a box of chocolates, you never know what you're gonna get
--

[Grant Edwards]

On 2008-03-15, Guido van Brakel <guidovb1@invalidwrote:

Hello

I have this now:

>def gem(a):
g = sum(a) / len(a)

g = float(sum(a)) / len(a)

> return g

It now gives a int, but i would like to see floats. How can integrate
that into the function?

See above.

Life is like a box of chocolates, you never know what you're gonna get

sometimes it's a crunchy frog...

--
Grant

[sturlamolden]

On 15 Mar, 22:43, Guido van Brakel <guidovb1@invalidwrote:

def gem(a):
g = sum(a) / len(a)
return g

It now gives a int, but i would like to see floats. How can integrate
that into the function?

You get an int because you are doing integer division. Cast one int to
float.

def gem(a):
g = sum(a) / float(len(a))
return g

[Guido van Brakel]

Grant Edwards wrote:

On 2008-03-15, Guido van Brakel <guidovb1@invalidwrote:

>Hello

I have this now:

>>def gem(a):
g = sum(a) / len(a)

g = float(sum(a)) / len(a)

>> return g

Hi,

Thank you very much,sometimes it is so amazing simple.

Regards

--
Guido van Brakel
Life is like a box of chocolates, you never know what you're gonna get
--

[sturlamolden]

On 15 Mar, 22:43, Guido van Brakel <guidovb1@invalidwrote:

def gem(a):
g = sum(a) / len(a)
return g

print gem([1,2,3,4])
print gem([1,10,100,1000])
print gem([1,-2,3,-4,5])

gem( map(float,[1,2,3,4]) )

gem( float(i) for i in [1,2,3,4] )

[Dan Bishop]

On Mar 15, 4:43 pm, Guido van Brakel <guidovb1@invalidwrote:

Hello

I have this now:

def gem(a):
g = sum(a) / len(a)
return g

print gem([1,2,3,4])
print gem([1,10,100,1000])
print gem([1,-2,3,-4,5])

It now gives a int, but i would like to see floats. How can integrate
that into the function?

If you add "from __future__ import division" at the top of the file,
division will work properly.

[Lie]

On Mar 16, 4:43*am, Guido van Brakel <guidovb1@invalidwrote:

Hello

I have this now:

def gem(a):
* * g = sum(a) / len(a)
* * return g

print gem([1,2,3,4])
print gem([1,10,100,1000])
print gem([1,-2,3,-4,5])

It now gives a int, but i would like to see floats. How can integrate
that into the function?

Regards,

--
Guido van Brakel
Life is like a box of chocolates, you never know what you're gonna get
--

Python 2's division operator's default behavior is to do integer
division whenever all of its operands are integers/long and do float
division if any of them are float/decimal, in Python 3, this is going
to be changed so that division would always be float division and
while integer division would have its own operator "//".

You can change the default behavior of Python 2 by importing division
behavior from __future__ module (from __future__ import division), or
you could convert one of the operands to float ("float(a) / b" or "a /
float(b)").

[Bryan Olson]

sturlamolden wrote:

Guido van Brakel wrote:

>>def gem(a):
g = sum(a) / len(a)
return g

>It now gives a int, but i would like to see floats. How can integrate
that into the function?

You get an int because you are doing integer division. Cast one int to
float.

def gem(a):
g = sum(a) / float(len(a))
return g

An alternative is to multiply by 1.0.

def gem(a):
g = 1.0 * sum(a) / len(a)
return g

The gem function is well-defined on sequences of complex numbers,
in which case the float() method will raise a TypeError, while
the 1.0* method will return the complex result. It may not be
what van Brakel wants here, but it's an alternative to keep in mind.

And I find it easier to type.

--
--Bryan