How to parse this timestamp?

[gnu.gcc.help]

I've got timestamps in a file that look like:

[19-Aug-2007 07:38:43+216ms NZST]

How can I parse them? I don't see any way to build a strftime()
format string that can handle the +216ms part. The best I can see is
tearing it all apart with a regex, but I'm trying to avoid that pain
if I can.

(PS: I have no clue why google groups thinks it should put
"gnu.gcc.help" on the from line)

[Miki]

Hello,

[19-Aug-2007 07:38:43+216ms NZST]

How can I parse them? *I don't see any way to build a strftime()
format string that can handle the +216ms part. The best I can see is
tearing it all apart with a regex, but I'm trying to avoid that pain
if I can.

(PS: I have no clue why google groups thinks it should put
"gnu.gcc.help" on the from line)

Just zap the end and use time.strptime:

>>s = '19-Aug-2007 07:38:43+216ms NZST'
strptime(re.sub("\+\d{3}ms [A-Z]{4}", "", s), "%d-%b-%Y %H:%M:%S")

(2007, 8, 19, 7, 38, 43, 6, 231, -1)

>>>

HTH,
--
Miki <mi*********@gmail.com>
http://pythonwise.blogspot.com

[Diez B. Roggisch]

gnu.gcc.help schrieb:

I've got timestamps in a file that look like:

[19-Aug-2007 07:38:43+216ms NZST]

How can I parse them? I don't see any way to build a strftime()
format string that can handle the +216ms part. The best I can see is
tearing it all apart with a regex, but I'm trying to avoid that pain
if I can.

(PS: I have no clue why google groups thinks it should put
"gnu.gcc.help" on the from line)

Then don't use the regexes. Use string.split to separate the string on
the +, then parse the left part with strptime, and usp pytz and
datetime.timedelta to do the rest.

Diez