file open dialog box

[yuva17raj]

hi
i am trying to get the file open dilog box such to choose the file from system(my computer) and after that i need to print the complete path of the selected file
i tried with sample applications allready posted but i con't get the dialog box itself
how to achive this task
i am implementing this in Activegrid
reply me ASAP

[dazzler]

I have no idea what's activegrid, can you use any python GUIs?

well anyway here's one example with tkinter...

from Tkinter import *
import tkFileDialog
 
 
master = Tk()
master.withdraw() #hiding tkinter window
 
file_path = tkFileDialog.askopenfilename(title="Open file", filetypes=[("txt file",".txt"),("All files",".*")])
 
if file_path != "":
   print "you chose file with path:", file_path
 
else:
   print "you didn't open anything!"
 
master.quit()