this didn't work elegantly as expected:
>>ss
'owi\nweoifj\nfheu\n'
>>re.split(r'\A',ss)
['owi\nweoifj\nfheu\n']
>>re.split(r'\Z',ss)
['owi\nweoifj\nfheu\n']
>>re.split(r'$',ss)
['owi\nweoifj\nfheu\n']
>>re.split(r'(?s)$',ss)
['owi\nweoifj\nfheu\n']
>>re.split(r'(?m)(?s)$',ss)
['owi\nweoifj\nfheu\n']
>>re.split(r'(?m)$',ss)
['owi\nweoifj\nfheu\n']
>>re.split(r'(?m)\Z',ss)
['owi\nweoifj\nfheu\n']
>>re.split(r'(?m)\A',ss)
['owi\nweoifj\nfheu\n']
>>re.split(r'(?s)\A',ss)
['owi\nweoifj\nfheu\n']
>>re.split(r'(?s)(?m)\A',ss)
['owi\nweoifj\nfheu\n']
>>>
how to do?
Robert 5  1330 
this didn't work elegantly as expected:
>
>>ss
'owi\nweoifj\nfheu\n'
>>re.split(r'(?m)$',ss)
['owi\nweoifj\nfheu\n']
Do you have a need to use a regexp?
>>ss.splitlines(True)
['owi\n', 'weoifj\n', 'fheu\n']
-tkc
Tim Chase wrote:
>this didn't work elegantly as expected:
> >>ss
'owi\nweoifj\nfheu\n'
> >>re.split(r'(?m)$',ss)
['owi\nweoifj\nfheu\n']
Do you have a need to use a regexp?
I'd like the general case - split without consumption.
>
>>>ss.splitlines(True)
['owi\n', 'weoifj\n', 'fheu\n']
thanks. Yet this does not work "naturally" consistent in my line
processing algorithm - the further buffering. Compare e.g.
ss.split('\n') ..
>>'owi\nweoifj\nfheu\n'.split('\n')
['owi', 'weoifj', 'fheu', '']
>>'owi\nweoifj\nfheu\nxx'.split('\n')
['owi', 'weoifj', 'fheu', 'xx']
is consistent in that regard: there is always a last empty or half
line, which can be fed readily as start to the further input
buffering.
With the .splitlines(True/False) results you need to fiddle, test
the last result's last char... Or you fail altogether with False.
So I'd call this a "wrong" implementation.
Robert
robert wrote:
thanks. Yet this does not work "naturally" consistent in my line
processing algorithm - the further buffering. Compare e.g.
ss.split('\n') Â*..
>'owi\nweoifj\nfheu\n'.split('\n')
['owi', 'weoifj', 'fheu', '']
>'owi\nweoifj\nfheu\nxx'.split('\n')
['owi', 'weoifj', 'fheu', 'xx']
Maybe this works for you?
>>re.split(r'(\n)', ss)
['owi', '\n', 'weoifj', '\n', 'fheu', '\n', '']
Jeffrey
Jeffrey Froman wrote:
robert wrote:
>thanks. Yet this does not work "naturally" consistent in my line
processing algorithm - the further buffering. Compare e.g.
ss.split('\n') ..
>>>>'owi\nweoifj\nfheu\n'.split('\n')
['owi', 'weoifj', 'fheu', '']
>>>>'owi\nweoifj\nfheu\nxx'.split('\n')
['owi', 'weoifj', 'fheu', 'xx']
Maybe this works for you?
>>>re.split(r'(\n)', ss)
['owi', '\n', 'weoifj', '\n', 'fheu', '\n', '']
Thanks, thats it
Robert
robert wrote:
[...]
but its also wrong regarding partial last lines.
re.split obviously doesn't understand \A \Z ^ $ and also \b etc.
empty matches.
[...]
Or perhaps you don't understand re?
It's a tricky thing to start playing with. Look up re.MULTILINE ans
re.DOTALL.
regards
Steve
--
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