Point Object

[pjmulla]

I am nes to python and need some help. Can anyone lead me in the
right direction to create and print a Point object, and then use id to
print the object's unique identifier. Translate the hexadecimal form
into decimal and confirm that they match.

Any help woul be much appreciated.

Pete

[Marc 'BlackJack' Rintsch]

On Sat, 05 Jan 2008 03:37:33 -0800, pj*****@googlemail.com wrote:

I am nes to python and need some help. Can anyone lead me in the
right direction to create and print a Point object, and then use id to
print the object's unique identifier. Translate the hexadecimal form
into decimal and confirm that they match.

The right direction would be the tutorial in the docs I guess:

http://docs.python.org/tut/tut.html

What do you mean by the "hexadecimal form"? `id()` returns ordinary
`int`\s and not strings.

Ciao,
Marc 'BlackJack' Rintsch

[Soviut]

On Jan 5, 6:37 am, "[e-mail]" <[e-mail]>
wrote:

I am nes to python and need some help. Can anyone lead me in the
right direction to create and print a Point object, and then use id to
print the object's unique identifier. Translate the hexadecimal form
into decimal and confirm that they match.

Any help woul be much appreciated.

Pete

You shouldn't have to compare the hex IDs. Just a simple comparison
operator will work:

firstPoint = Point()
secondPoint = Point()
print(firstPoint == secondPoint)

result: True

[bearophileHUGS]

Pete:

Translate the hexadecimal form
into decimal and confirm that they match.

No need to convert the IDs...
Soviut:

You shouldn't have to compare the hex IDs. Just a simple comparison
operator will work:

firstPoint = Point()
secondPoint = Point()
print(firstPoint == secondPoint)

result: True

Remember about __eq__ and "is":

class Foo:
def __init__(self, x):
self.x = x
def __eq__(self, other):
return self.x == other.x

f1 = Foo(1)
f2 = Foo(2)
f3 = Foo(2)
f4 = f3
print f1 == f2, f1 is f2 # False False
print f2 == f3, f2 is f3 # True False
print f3 == f4, f3 is f4 # True True

Bye,
bearophile