argv[0] and __file__ inconsistency

[Hai Vu]

I currently use ActivePython 2.5.1. Consider the following code which
I saved as cmdline.py:
import sys
print sys.argv[0]
If I invoke this code as 'python cmdline.py', then the output is:
cmdline.py
If I invoke it as 'cmdline.py', then the output is:
C:\Users\hai\src\python\cmdline.py

The same happens for __file__. My question: do you have any
suggestions for a more consistent way to figure out the full path of
your script?

[John Machin]

On Jan 1, 9:31 am, Hai Vu <[e-mail]:

I currently use ActivePython 2.5.1. Consider the following code which
I saved as cmdline.py:
import sys
print sys.argv[0]
If I invoke this code as 'python cmdline.py', then the output is:
cmdline.py
If I invoke it as 'cmdline.py', then the output is:
C:\Users\hai\src\python\cmdline.py

The same happens for __file__. My question: do you have any
suggestions for a more consistent way to figure out the full path of
your script?

use os.path.abspath

[Benjamin M. A'Lee]

On Mon, Dec 31, 2007 at 02:31:39PM -0800, Hai Vu wrote:

I currently use ActivePython 2.5.1. Consider the following code which
I saved as cmdline.py:
import sys
print sys.argv[0]
If I invoke this code as 'python cmdline.py', then the output is:
cmdline.py
If I invoke it as 'cmdline.py', then the output is:
C:\Users\hai\src\python\cmdline.py

The same happens for __file__. My question: do you have any
suggestions for a more consistent way to figure out the full path of
your script?

How about::

from os.path import abspath
scriptname = abspath(sys.argv[0])

-----BEGIN PGP SIGNATURE-----
Version: GnuPG v1.4.6 (GNU/Linux)

iD8DBQFHeXXuEUZDNrttL6ARAh+6AKDIuqZr76t94DnRWtULHX mZEY7oNgCgklEr
Nnzko5YaVkEa7Tlanz/0Ehk=
=b4SC
-----END PGP SIGNATURE-----