On 28 dic, 20:12, Riccardo Murri <riccardo.mu...@gmail.comwrote:
The list `self.base` contains "canonical" forms of the graphs and the
`graph` object must compare equal to some item of the list, which
indeed it does::
* (Pydb) p graph == self.base[27] *
* True
* (Pydb) p graph in self.base
* True
However, I cannot directly get the index of the canonical graph (the
number "27" above was found by manual inspection)::
* (Pydb) self.base.index(graph)
* *** ValueError: list.index(x): x not in list
All graphs are instances of a `Graph` new-style class that implements
comparison operators `__eq__` and `__ne__`, but no other rich-compare
stuff.
I'm using Python 2.5::
* Python 2.5 (release25-maint, Dec *9 2006, 16:17:58)
* [GCC 4.1.2 20061115 (prerelease) (Debian 4.1.1-20)] on linux2
So my question is: what are the implementation differences between `x
in list` and `list.index(x)` and why can one report that an item is in
the list while the other cannot find its index? *Should I add
something to the `Graph` class so that `index` works?
(I've checked on 2.5.1 but I don't see any relevant differences with
the 2.5 version). Looking at the source for both methods, they only
use the __eq__ operator, but there is a slight difference: while one
evaluates list[i]==x, the other reverses the operands. If your __eq__
is not reflexive, that could explain the difference.
class Graph(object):
def __init__(self, *items):
self.items = items
def __eq__(self, other):
if len(self.items)>len(other.items): return False
return self.items == other.items[:len(self.items)]
pyList = [Graph(1,2,3), Graph(4,5,6), Graph(1,2,3,4)]
pyg = Graph(1,2)
pyg in List
True
pyList.index(g)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
ValueError: list.index(x): x not in list
pyList[0]==g
False
pyg==List[0]
True
In your example, see if self.base[27]==graph is still True.
--
Gabriel Genellina
