how to open a directory containing many files?

[aboxylica]

i know how to open a file and access its elements..now i have to open a folder containing these files and work with these files..
the normal open("directoryname") is giving me an error.
any suggestions??
looking for ur reply!
cheers!

[ghostdog74]

i know how to open a file and access its elements..now i have to open a folder containing these files and work with these files..
the normal open("directoryname") is giving me an error.
any suggestions??
looking for ur reply!
cheers!

check out os.listdir() or os.walk().

[aboxylica]

check out os.listdir() or os.walk().

i kind of tried checking how this command really works in google i could not really understand.
what i typically want to do is th
file=open("filename","r")
instead of this i want to open the directory containing these files.
file=open("directoryname","r")
when i use

import os
seq=os.listdir(directory name")
 

doesnt seem to work
waiting for ur reply,
cheers!

[ghostdog74]

i kind of tried checking how this command really works in google i could not really understand.
what i typically want to do is th
file=open("filename","r")
instead of this i want to open the directory containing these files.
file=open("directoryname","r")
when i use

import os
seq=os.listdir(directory name")
 

doesnt seem to work
waiting for ur reply,
cheers!

what doesn't seem to work? did you print out the seq variable and see if there's any values?

seq = os.listdir("directory")
print seq
 
 

[bvdet]

i kind of tried checking how this command really works in google i could not really understand.
what i typically want to do is th
file=open("filename","r")
instead of this i want to open the directory containing these files.
file=open("directoryname","r")
when i use

import os
seq=os.listdir(directory name")
 

doesnt seem to work
waiting for ur reply,
cheers!

You cannot open a directory with the built-in function file(). You can create a filtered list of files found in a specific directory with the os module.

>>> import os
# Create a list of directory entries
>>> dir_name = 'X:\\TEMP\\temp'
>>> fList = os.listdir(dir_name)
# The directory entries do not include the full path
# Create a list of file names with full path, eliminating subdirectory entries
>>> fList1 = [os.path.join(dir_name, f) for f in fList if os.path.isfile(os.path.join(dir_name, f))]

Alternatively, you can change your current working directory with os.chdir() and you will not need the full path to access the files.

[aboxylica]

okay, that kind of works.that lists the file which i can handle
but to get into the files..this is what am trying

import os
seq=os.listdir("ding")
print seq
# this lists all the file
for i,rem in enumerate(seqq):
rem=open("i","r")
print rem
 
 

this does not seem to work.
waiting for reply,
cheers!

[bvdet]

okay, that kind of works.that lists the file which i can handle
but to get into the files..this is what am trying

import os
seq=os.listdir("ding")
print seq
# this lists all the file
for i,rem in enumerate(seqq):
    rem=open("i","r")
    print rem
 
 

this does not seem to work.
waiting for reply,
cheers!

Try this (untested):

import os
seq=os.listdir("ding")
print seq
os.chdir("ding")
for f in seq:
    if os.path.isfile(f):
        rem = open("f")
        print rem.read()
        rem.close()

[aboxylica]

thanks a lot..that helped!