Regex homeworks

[cobraro22]

i have 2 homeworks

i have to make 2 functions

1. to extract all words with literal doubled

example
text = "use the foot to hit the ball and score a goooal, and be happy."
with
print re.findall(r'XXX',text)
have to return foot,ball,gooal,happy

2. to extract all names

text = """Ms and Mr Smith decided to visit Mrs Ann Anderson. When they crossed
the Mraselrow Street they met Somebody; it was the well known Dr Jones. They talked
about Dr Ali Baba and his 40 Assistants. Mr Nada was nowhere to be found, but
Ms Rosette Rose, Ms R Fitzgeral and Mr Van Der Valt were Ok."""

print re.findall(r'XXX',text)
shoult print

Smith, Ann Anderson, Jones, Ali Baba, Nada, Rosette Rose, R Fitzgeral, Van Der Valt

[oler1s]

The homework assignment looks straightforward to me. Was there a question you had about it, or the code you were writing?

[cobraro22]

print re.findall(r'XXX',text)

XXX - regexpression for print what i want

[bvdet]

print re.findall(r'XXX',text)

XXX - regexpression for print what i want

Do you expect us to provide the answer to your homework? You cannot learn that way. Show us some effort to solve the problem on your own, and maybe someone can help you from there. Following is a way for problem #1 that seems a lot simpler than regex:

import string
textList = text.split()
results = []
for word in textList:
    for i, letter in enumerate(word):
        try:
            if word[i+1] == letter:
                results.append(word.strip(string.punctuation))
                break
        except IndexError, e:
            break
 
print results

Output:

>>> ['foot', 'ball', 'goooal', 'happy']

[cobraro22]

u don`t understand me
i have to print using reg expressions

like example here

import re
 
def find_thousand():
    """
    Write a regular expression that matches numbers
    that are written using "'" as thousand separator:
    >>> find_thousand()
    124 1,234 4,321,434 234,231 987,654,321,333,551
    """
    text = """Go:124 is not 1,234 nor 1233 and  3,14 12,12 din 70,
              definetly yes 4,321,434 div 234,231 987,654,321,333,551"""
    f  =  re.findall(r''' (?<![\d,])                # it is not preceded by other digit or comma
                          (\d{1,3}                  # has 1..3 digits
                          (,\d{3})*)                # possibly followed by comma and groups of 3 digits
                          (?![\d,])                 # and at the end has no other digit or comma
                          ''', text, re.VERBOSE)
    print " ".join([i[0] for i in f])

for my homework
[HTML]
def count_doubles():
"""
Find all the words that contain double letters inside them (or at the end)
For the provided text the routine should behave like this:
>>> count_doubles()
foot, ball, goooal, happy
"""
text = "use the foot to hit the ball and score a goooal, and be happy. i i i'll go."[/HTML]

I have to make my homework only with regular expression

[bvdet]

u don`t understand me
i have to print using reg expressions

like example here

import re
 
def find_thousand():
    """
    Write a regular expression that matches numbers
    that are written using "'" as thousand separator:
    >>> find_thousand()
    124 1,234 4,321,434 234,231 987,654,321,333,551
    """
    text = """Go:124 is not 1,234 nor 1233 and  3,14 12,12 din 70,
              definetly yes 4,321,434 div 234,231 987,654,321,333,551"""
    f  =  re.findall(r''' (?<![\d,])                # it is not preceded by other digit or comma
                          (\d{1,3}                  # has 1..3 digits
                          (,\d{3})*)                # possibly followed by comma and groups of 3 digits
                          (?![\d,])                 # and at the end has no other digit or comma
                          ''', text, re.VERBOSE)
    print " ".join([i[0] for i in f])

for my homework
[HTML]
def count_doubles():
"""
Find all the words that contain double letters inside them (or at the end)
For the provided text the routine should behave like this:
>>> count_doubles()
foot, ball, goooal, happy
"""
text = "use the foot to hit the ball and score a goooal, and be happy. i i i'll go."[/HTML]

I have to make my homework only with regular expression

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