Check if a symlink is broken or circular

[Giampaolo Rodola']

Hi there,
I would like to know if such function would be correct for verifying
if a link is broken and/or circular.

def isvalidlink(path):
assert os.path.islink(path)
try:
os.stat(path)
except os.error:
return 1
return 0

[=?ISO-8859-1?Q?=22Martin_v=2E_L=F6wis=22?=]

I would like to know if such function would be correct for verifying

if a link is broken and/or circular.

def isvalidlink(path):
assert os.path.islink(path)
try:
os.stat(path)
except os.error:
return 1
return 0

You meant to flip the result values, right? 1 should mean that the
link is value, and 0 that it is not.

Mostly. If the link is correct, but you don't have permission to stat
the target file, you get 0. OTOH, in that case, you have no way of
finding out whether the link *is* correct.

Still, you could try to detect the errnos that indicate a problem
with the link itself, and pass all other errors through.

Regards,
Martin

[Giampaolo Rodola']

On 1 Dic, 00:10, "Martin v. Löwis" <[e-mail]:

I would like to know if such function would be correct for verifying
if a link is broken and/or circular.

def isvalidlink(path):
assert os.path.islink(path)
try:
os.stat(path)
except os.error:
return 1
return 0

You meant to flip the result values, right? 1 should mean that the
link is value, and 0 that it is not.

Mostly. If the link is correct, but you don't have permission to stat
the target file, you get 0. OTOH, in that case, you have no way of
finding out whether the link *is* correct.

Still, you could try to detect the errnos that indicate a problem
with the link itself, and pass all other errors through.

Regards,
Martin

Mmmm... do you mean something like this?
Could it be ok?

import os, errno

def isvalidlink(path):
assert os.path.lexists(path)
try:
os.stat(path)
except os.error, err:
# broken link
# "No such file or directory"
if err.errno == errno.ENOENT:
return 1
# circular link
# "Too many levels of symlinks"
elif err.errno == errno.ELOOP:
return 2
# something else occurred,
# assume it as invalid anyway
else:
return 3
return 0

[davisn90210]

Giampaolo Rodola' wrote:

On 1 Dic, 00:10, "Martin v. L�wis" <[e-mail]:

I would like to know if such function would be correct for verifying
if a link is broken and/or circular.

def isvalidlink(path):
assert os.path.islink(path)
try:
os.stat(path)
except os.error:
return 1
return 0

You meant to flip the result values, right? 1 should mean that the
link is value, and 0 that it is not.

Mostly. If the link is correct, but you don't have permission to stat
the target file, you get 0. OTOH, in that case, you have no way of
finding out whether the link *is* correct.

Still, you could try to detect the errnos that indicate a problem
with the link itself, and pass all other errors through.

Regards,
Martin

Mmmm... do you mean something like this?
Could it be ok?

I think he meant something like this (see below):

>
import os, errno

def isvalidlink(path):
assert os.path.lexists(path)
try:
os.stat(path)
except os.error, err:
# broken link
# "No such file or directory"
if err.errno == errno.ENOENT:
return 1

Right, except that it should be return 0 (or preferably return False)
unless you want inverted logic.

# circular link
# "Too many levels of symlinks"
elif err.errno == errno.ELOOP:
return 2

Change to return 1/True (inverted) or return 0/False (not inverted)

# something else occurred,
# assume it as invalid anyway
else:
return 3

Change "return 3" to "raise", so the exception gets propagated.

return 0

Again, if you do not want the logic to be inverted, use return 1/True
instead

--Nathan Davis