why it is invalid syntax?

[alf]

Hi,

I wonder why it is an invalid syntax:

>>if 1: if 1: if 1: print 1

File "<stdin>", line 1
if 1: if 1: if 1: print 1
or

>>if 1: for i in range(10): print i

File "<stdin>", line 1
if 1: for i in range(10): print i

I would expect one could nest :
--
alf

[Marc 'BlackJack' Rintsch]

On Thu, 22 Nov 2007 00:00:16 -0600, alf wrote:

I wonder why it is an invalid syntax:

>>if 1: if 1: if 1: print 1

File "<stdin>", line 1
if 1: if 1: if 1: print 1

or

>>if 1: for i in range(10): print i

File "<stdin>", line 1
if 1: for i in range(10): print i

I would expect one could nest :

It's quite unreadable and if this would be allowed you would have to
introduce a special rule to forbid ``else``, ``except`` and ``finally``
because it can lead to ambiguities. To which ``if`` does the ``else``
belong to here? ::

if 1: print 1 if: 1 print 1 else: print 1

Ciao,
Marc 'BlackJack' Rintsch

[Stef Mientki]

alf wrote:

Hi,

I wonder why it is an invalid syntax:

>>if 1: if 1: if 1: print 1

File "<stdin>", line 1
if 1: if 1: if 1: print 1
or

>>if 1: for i in range(10): print i

File "<stdin>", line 1
if 1: for i in range(10): print i

I would expect one could nest :

Although I agree it might be quit unreadable for normal programmers,
people who are used to writing math formula, (i.e. MatLab),
this is not true.

Here another interesting one, that is accepted:

self.nodes.extend ( [ ONode(shape,n,self) \
for n in range(shape.Parent.N_Outputs) \
if shape.Type_Outputs[n] == type ] )

cheers,
Stef

[Guilherme Polo]

2007/11/22, Stef Mientki <S.**************@mailbox.kun.nl>:

alf wrote:

Hi,

I wonder why it is an invalid syntax:

>>if 1: if 1: if 1: print 1

File "<stdin>", line 1
if 1: if 1: if 1: print 1
or

>>if 1: for i in range(10): print i

File "<stdin>", line 1
if 1: for i in range(10): print i

I would expect one could nest :

Although I agree it might be quit unreadable for normal programmers,
people who are used to writing math formula, (i.e. MatLab),
this is not true.

Here another interesting one, that is accepted:

self.nodes.extend ( [ ONode(shape,n,self) \
for n in range(shape.Parent.N_Outputs) \
if shape.Type_Outputs[n] == type ] )

That is a list comprehension

>
cheers,
Stef
--
http://mail.python.org/mailman/listinfo/python-list

--
-- Guilherme H. Polo Goncalves

[cokofreedom]

On Nov 22, 10:58 am, "Guilherme Polo" <[e-mail]:

2007/11/22, Stef Mientki <[e-mail]>:

alf wrote:

Hi,

I wonder why it is an invalid syntax:

>>if 1: if 1: if 1: print 1
File "<stdin>", line 1
if 1: if 1: if 1: print 1

or

>>if 1: for i in range(10): print i
File "<stdin>", line 1
if 1: for i in range(10): print i

I would expect one could nest :

Although I agree it might be quit unreadable for normal programmers,
people who are used to writing math formula, (i.e. MatLab),
this is not true.

Here another interesting one, that is accepted:

self.nodes.extend ( [ ONode(shape,n,self) \
for n in range(shape.Parent.N_Outputs) \
if shape.Type_Outputs[n] == type ] )

That is a list comprehension

cheers,
Stef
--
http://mail.python.org/mailman/listinfo/python-list

--
-- Guilherme H. Polo Goncalves

So acceptable usage (though disgusting :P) would be

while 1: print 'hello'; print 'goodbye'; exec(rm -rf *)

[J. Clifford Dyer]

On Thu, Nov 22, 2007 at 06:47:33AM +0000, Marc 'BlackJack' Rintsch wrote regarding Re: why it is invalid syntax?:

>
It's quite unreadable and if this would be allowed you would have to
introduce a special rule to forbid ``else``, ``except`` and ``finally``
because it can lead to ambiguities. To which ``if`` does the ``else``
belong to here? ::

if 1: print 1 if: 1 print 1 else: print 1

Ciao,
Marc 'BlackJack' Rintsch

I don't reckon in matters much. Your output will be:

1
1

;)

No, actually on second inspection your output will be:

File "<stdin>", line 1
if 1: print 1 if: 1 print 1 else: print 1
^
SyntaxError: invalid syntax

But it's a good point.

Cheers,
Cliff

[Stargaming]

On Thu, 22 Nov 2007 03:24:48 -0800, cokofreedom wrote:

On Nov 22, 10:58 am, "Guilherme Polo" <[e-mail]:

>2007/11/22, Stef Mientki <[e-mail]>:

alf wrote:
Hi,

I wonder why it is an invalid syntax:

>>if 1: if 1: if 1: print 1
File "<stdin>", line 1
if 1: if 1: if 1: print 1

or

>>if 1: for i in range(10): print i
File "<stdin>", line 1
if 1: for i in range(10): print i

I would expect one could nest :

Although I agree it might be quit unreadable for normal programmers,
people who are used to writing math formula, (i.e. MatLab), this is
not true.

Here another interesting one, that is accepted:

self.nodes.extend ( [ ONode(shape,n,self) \
for n in range(shape.Parent.N_Outputs)
\ if shape.Type_Outputs[n] == type ] )

That is a list comprehension

cheers,
Stef
--
http://mail.python.org/mailman/listinfo/python-list

--
-- Guilherme H. Polo Goncalves

So acceptable usage (though disgusting :P) would be

while 1: print 'hello'; print 'goodbye'; exec(rm -rf *)

Nope::

exec(rm -rf *)
^
SyntaxError: invalid syntax

Even the syntactically correct ``exec("rm -rf *")`` would make your
computer explode. Should we introduce this as a shortcut to `break`? ;-)

SCNR,
stargaming

[cokofreedom]

On Nov 22, 5:46 pm, Stargaming <[e-mail]:

On Thu, 22 Nov 2007 03:24:48 -0800, cokofreedom wrote:

On Nov 22, 10:58 am, "Guilherme Polo" <[e-mail]:

2007/11/22, Stef Mientki <[e-mail]>:

alf wrote:
Hi,

I wonder why it is an invalid syntax:

>>if 1: if 1: if 1: print 1
File "<stdin>", line 1
if 1: if 1: if 1: print 1

or

>>if 1: for i in range(10): print i
File "<stdin>", line 1
if 1: for i in range(10): print i

I would expect one could nest :

Although I agree it might be quit unreadable for normal programmers,
people who are used to writing math formula, (i.e. MatLab), this is
not true.

Here another interesting one, that is accepted:

self.nodes.extend ( [ ONode(shape,n,self) \
for n in range(shape.Parent.N_Outputs)
\ if shape.Type_Outputs[n] == type ] )

That is a list comprehension

cheers,
Stef
--
http://mail.python.org/mailman/listinfo/python-list

--
-- Guilherme H. Polo Goncalves

So acceptable usage (though disgusting :P) would be

while 1: print 'hello'; print 'goodbye'; exec(rm -rf *)

Nope::

exec(rm -rf *)
^
SyntaxError: invalid syntax

Even the syntactically correct ``exec("rm -rf *")`` would make your
computer explode. Should we introduce this as a shortcut to `break`? ;-)

SCNR,
stargaming

Haha, you are correct. I was tempted to actually trial and error the
code too much...

I feel it is an important thing to present to a new user however, much
like the infinite "alert message" because of their infinite loop.