1. whats the best way to round a result to 4 decimal places?
I tried round, but then read that it only works with exponents of 10.
I'm trying to do it on this piece of code.
time = (distance / 4900)
2. What direction would I go in if I'm getting 5 inputs from the user
and want to make a bar table out of them where a * represents a 100 of
the total number?
For example,
Store 1: * *
Store 2: *
Store 3: * * *
ect,
I already know I'm going to be expecting to use a for loop (0,4) since
there are 5 inputs, but how to get from say, 200 to the output of * *
I'm a little lost.
thx 2 955
Shawn Minisall wrote:
1. whats the best way to round a result to 4 decimal places?
I tried round, but then read that it only works with exponents of 10.
I'm trying to do it on this piece of code.
time = (distance / 4900)
2. What direction would I go in if I'm getting 5 inputs from the user
and want to make a bar table out of them where a * represents a 100 of
the total number?
For example,
Store 1: * *
Store 2: *
Store 3: * * *
ect,
I already know I'm going to be expecting to use a for loop (0,4) since
there are 5 inputs, but how to get from say, 200 to the output of * *
I'm a little lost.
thx
Q:1
>>round(123.45678, 4)
123.4568
Q2:
Something like this works:
stores=[]
for i in xrange(0,5):
x=raw_input("input number for store=%i ?" % i)
stores.append(int(x))
for i in xrange(0,5):
hundreds, remainder=divmod(stores[i], 100)
print "Store: %i %s" % (i+1, hundreds*"*")
-Larry
On Oct 31, 10:10 pm, Larry Bates <larry.ba...@websafe.comwrote:
for i in xrange(0,5):
hundreds, remainder=divmod(stores[i], 100)
print "Store: %i %s" % (i+1, hundreds*"*")
Yes, or since you don't need 'remainder'...
for i in range(5):
hundreds = stores[i] // 100
print "Store: %i %s" % (i + 1, '*' * hundreds)
--
Paul Hankin This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics
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