Geometrical mean

[DDCane]

I need to define a function "geomean(numbers)" that takes all the numbers in the list, adds then together then takes the sum of the numbers and puts it to the power of 1/how many numbers there are in the list. the resulty should be something like this:

geomean([1,2,3,4])

1+2+3+4=10

10^(1/4)

do yall get what im trying to say? when i read what i just wrote its hard for ME to follow it.

if u look up geometrical mean on wikepedia you'll get a better understanding of what im trying to do.

[ilikepython]

I need to define a function "geomean(numbers)" that takes all the numbers in the list, adds then together then takes the sum of the numbers and puts it to the power of 1/how many numbers there are in the list. the resulty should be something like this:

geomean([1,2,3,4])

1+2+3+4=10

10^(1/4)

do yall get what im trying to say? when i read what i just wrote its hard for ME to follow it.

if u look up geometrical mean on wikepedia you'll get a better understanding of what im trying to do.

Like this?

def geomean(num_list):
    return sum(num_list) ** (1.0/len(num_list))
 

[KaezarRex]

I need to define a function "geomean(numbers)" that takes all the numbers in the list, adds then together then takes the sum of the numbers and puts it to the power of 1/how many numbers there are in the list. the resulty should be something like this:

geomean([1,2,3,4])

1+2+3+4=10

10^(1/4)

do yall get what im trying to say? when i read what i just wrote its hard for ME to follow it.

if u look up geometrical mean on wikepedia you'll get a better understanding of what im trying to do.

I hate to be a stickler on math, but the geometric mean of [1, 2, 3, 4] is (1*2*3*4)^(1/4)

def geomean(numbers):
    product = 1
    for n in numbers:
        product *= n
    return product ** (1.0/len(numbers))

[bvdet]

I hate to be a stickler on math, but the geometric mean of [1, 2, 3, 4] is (1*2*3*4)^(1/4)

def geomean(numbers):
    product = 1
    for n in numbers:
        product *= n
    return product ** (1.0/len(numbers))

Good work KaezarRex. Here is the same calculation using reduce():

def geomean(nums):
    return (reduce(lambda x, y: x*y, nums))**(1.0/len(nums))
 
nums = (1,2,3,4,5)
print geomean(nums)

>>> 2.6051710847

[KaezarRex]

Good work KaezarRex. Here is the same calculation using reduce():

def geomean(nums):
    return (reduce(lambda x, y: x*y, nums))**(1.0/len(nums))
 
nums = (1,2,3,4,5)
print geomean(nums)

>>> 2.6051710847

Nice! I knew there had to be a way to use reduce, but I have never used lambda before. Thanks for the example.