471,334 Members | 1,433 Online
Bytes | Software Development & Data Engineering Community
Post +

Home Posts Topics Members FAQ

Join Bytes to post your question to a community of 471,334 software developers and data experts.

How to implement function like this?

Hello gurus,

I have a question, a function like below, it is implemented by me, :)

def funcA(tarray):
a = [2,3,4]
if len(tarray) >=3:
return a[0],a[1], a[2]
elif len(tarray) == 2:
return a[0],a[1], funcB(1)[0]
elif len(tarray) == 1:
return a[0], funcB(2)[0], funcB(2)[1]
else:
return funcB(3)[0], funcB(3)[1], funcB(3)[2]
The return of funcA is always 3 values, but depending on the length of
tarray, I need to return different values accordingly. if tarray lenght is
2, I need to get another one value from funcB, if tarray length is 0, I need
to get all three values from funcB.
Is there a brief way to achieve it?

Thanks,
Oct 23 '07 #1
5 1156
On Tue, 23 Oct 2007 16:28:37 +0800, Yinghe Chen wrote:
Hello gurus,

I have a question, a function like below, it is implemented by me, :)

def funcA(tarray):
a = [2,3,4]
if len(tarray) >=3:
return a[0],a[1], a[2]
elif len(tarray) == 2:
return a[0],a[1], funcB(1)[0]
elif len(tarray) == 1:
return a[0], funcB(2)[0], funcB(2)[1]
else:
return funcB(3)[0], funcB(3)[1], funcB(3)[2]
The return of funcA is always 3 values, but depending on the length of
tarray, I need to return different values accordingly. if tarray lenght is
2, I need to get another one value from funcB, if tarray length is 0, I need
to get all three values from funcB.
Untested:

def func_a(t_array):
result = [2, 3, 4]
t_array_length = len(t_array)
remaining_length = len(result) - t_array_length
if t_array_length < len(result):
result = (result[:t_array_length]
+ func_b(remaining_length)[:remaining_length])
return tuple(result)

Ciao,
Marc 'BlackJack' Rintsch
Oct 23 '07 #2
"Yinghe Chen" <yi*********@jeppesen.com.rmwrites:
def funcA(tarray):
a = [2,3,4]
if len(tarray) >=3:
return a[0],a[1], a[2]
elif len(tarray) == 2:
return a[0],a[1], funcB(1)[0]
elif len(tarray) == 1:
return a[0], funcB(2)[0], funcB(2)[1]
else:
return funcB(3)[0], funcB(3)[1], funcB(3)[2]
untested:

from itertools import chain, islice
def funcA(tarray):
xB = max(3 - len(tarray), 0)
return chain(a, islice(funcB(xB), xB))
Oct 23 '07 #3
even shorter:

def funcA(tarray):
s = min(len(tarray), 3)
return [2, 3, 4][0:s] + [e for e in funcB(3-s)[0:3-s]]
Oct 23 '07 #4
On Tue, 23 Oct 2007 11:48:08 +0200, Loic Mahe wrote:
even shorter:

def funcA(tarray):
s = min(len(tarray), 3)
return [2, 3, 4][0:s] + [e for e in funcB(3-s)[0:3-s]]
Why the list comprehension!?

Ciao,
Marc 'Blackjack' Rintsch
Oct 23 '07 #5
Marc 'BlackJack' Rintsch a écrit :
On Tue, 23 Oct 2007 11:48:08 +0200, Loic Mahe wrote:
>even shorter:

def funcA(tarray):
s = min(len(tarray), 3)
return [2, 3, 4][0:s] + [e for e in funcB(3-s)[0:3-s]]

Why the list comprehension!?

Ciao,
Marc 'Blackjack' Rintsch
sorry I just read too fast
and thought he worked with lists ...
anyway 'e for e in' and so list comprehension was useless here

def funcA(tarray):
s = min(len(tarray), 3)
return (2, 3, 4,)[0:s] + funcB(3-s)[0:3-s]

this is ok if funcB(...) returns a tuple ...
if it returns a list just add: tuple(funcB(...))

note: list comprehension transforms a tuple into a list
Oct 23 '07 #6

This discussion thread is closed

Replies have been disabled for this discussion.

Similar topics

1 post views Thread by wukexin | last post: by
7 posts views Thread by Don | last post: by
4 posts views Thread by GrandpaB | last post: by
3 posts views Thread by alex | last post: by
reply views Thread by emin.shopper | last post: by
19 posts views Thread by UG | last post: by
reply views Thread by rosydwin | last post: by

By using Bytes.com and it's services, you agree to our Privacy Policy and Terms of Use.

To disable or enable advertisements and analytics tracking please visit the manage ads & tracking page.