int to str in list elements..

[Abandoned]

Hi..
I have a list as a=[1, 2, 3 .... ] (4 million elements)
and
b=",".join(a)
than
TypeError: sequence item 0: expected string, int found
I want to change list to a=['1','2','3'] but i don't want to use FOR
because my list very very big.
I'm sorry my bad english.
King regards

[Tobias K.]

1. Use a generator expression:
b = ",".join(str(i) for i in a)

or

2. Use imap
from itertools import imap
b = ",".join(imap(str, a))

[John Machin]

On Oct 15, 4:02 am, Abandoned <[e-mail]:

Hi..
I have a list as a=[1, 2, 3 .... ] (4 million elements)
and
b=",".join(a)
than
TypeError: sequence item 0: expected string, int found
I want to change list to a=['1','2','3'] but i don't want to use FOR
because my list very very big.

What is your worry: memory or time? The result string will be very
very very big. What will you do with the result string -- write it to
a file? If so, look at the cPickle module.

[Alex Martelli]

Abandoned <be*****@gmail.comwrote:

Hi..
I have a list as a=[1, 2, 3 .... ] (4 million elements)
and
b=",".join(a)
than
TypeError: sequence item 0: expected string, int found
I want to change list to a=['1','2','3'] but i don't want to use FOR
because my list very very big.
I'm sorry my bad english.
King regards

Try b=','.join(map(str, a)) -- it WILL take up some memory (temporarily)
to build the huge resulting string, but there's no real way to avoid
that.

It does run a bit faster than a genexp with for...:

brain:~ alex$ python -mtimeit -s'a=range(4000*1000)'
'b=",".join(map(str,a))'
10 loops, best of 3: 3.37 sec per loop

brain:~ alex$ python -mtimeit -s'a=range(4000*1000)' 'b=",".join(str(x)
for x i
n a)'
10 loops, best of 3: 4.36 sec per loop
Alex

[Tim Roberts]

John Machin <sj******@lexicon.netwrote:

>On Oct 15, 4:02 am, Abandoned <[e-mail]:

>Hi..
I have a list as a=[1, 2, 3 .... ] (4 million elements)
and
b=",".join(a)
than
TypeError: sequence item 0: expected string, int found
I want to change list to a=['1','2','3'] but i don't want to use FOR
because my list very very big.

What is your worry: memory or time? The result string will be very
very very big.

It's an interesting mental exercise to try to figure out just how large
that string will be, without using Python.

I get 30,888,889 bytes...
--
Tim Roberts, ti**@probo.com
Providenza & Boekelheide, Inc.

[Marc 'BlackJack' Rintsch]

On Tue, 16 Oct 2007 06:18:51 +0000, Tim Roberts wrote:

John Machin <sj******@lexicon.netwrote:

>>On Oct 15, 4:02 am, Abandoned <[e-mail]:

>>Hi..
I have a list as a=[1, 2, 3 .... ] (4 million elements)
and
b=",".join(a)
than
TypeError: sequence item 0: expected string, int found
I want to change list to a=['1','2','3'] but i don't want to use FOR
because my list very very big.

What is your worry: memory or time? The result string will be very
very very big.

It's an interesting mental exercise to try to figure out just how large
that string will be, without using Python.

I get 30,888,889 bytes...

I think you have an off by one error here. (One number, not one byte) :-)

Ciao,
Marc 'BlackJack' Rintsch

[John Machin]

Marc 'BlackJack' Rintsch wrote:

On Tue, 16 Oct 2007 06:18:51 +0000, Tim Roberts wrote:

John Machin <sj******@lexicon.netwrote:

>On Oct 15, 4:02 am, Abandoned <[e-mail]:
Hi..
I have a list as a=[1, 2, 3 .... ] (4 million elements)
and
b=",".join(a)
than
TypeError: sequence item 0: expected string, int found
I want to change list to a=['1','2','3'] but i don't want to use FOR
because my list very very big.

What is your worry: memory or time? The result string will be very
very very big.

It's an interesting mental exercise to try to figure out just how large
that string will be, without using Python.

I get 30,888,889 bytes...

I think you have an off by one error here. (One number, not one byte) :-)

It's certainly off :

[Best viewed in a fixed-width font ... umm, do they still sell squared
paper for doing arithmetic on? I had to rip a page out of a notebook
and rotate it through 90 degrees]
3000001 x 8 = 24000008
0900000 x 7 = 06300000
0090000 x 6 = 00540000
0009000 x 5 = 00045000
0000900 x 4 = 00003600
0000090 x 3 = 00000270
0000009 x 2 = 00000018
------- --------
4000000 30888896
less one for a comma counted above but not used -30888895
difference is 6 bytes which is one number (8) LESS 2 bytes

Cheers,
John