determining fully qualified package & class name

[patrimith]

Hi List,

I am used to the following with Java:

import some.package.MyClass;
name = MyClass.class.getName();

The value for name will be "some.package.MyClass".

For Python, I find:

from some.package.myclass import MyClass
name = MyClass.__name__

The value for name will be "MyClass"

Is there a comparable way to get the fully qualified name (package, module,
and class name) in Python?

Thanks,
Patrick Smith
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[Marc 'BlackJack' Rintsch]

On Thu, 11 Oct 2007 11:18:33 -0700, patrimith wrote:

I am used to the following with Java:

import some.package.MyClass;
name = MyClass.class.getName();

The value for name will be "some.package.MyClass".

For Python, I find:

from some.package.myclass import MyClass
name = MyClass.__name__

The value for name will be "MyClass"

Is there a comparable way to get the fully qualified name (package, module,
and class name) in Python?

Take a look at the `__module__` attribute of the class.

Ciao,
Marc 'BlackJack' Rintsch

[Goldfish]

import myPackage

f = myPackage.foo()

print f.__module__ + "." + f.__class__.__name__

That should do it!