Wrapper functions and arguments

[Jeremy Sanders]

One little issue I have is to write a little wrapper which can generally
pass standard and keyword arguments to a callee:

def a(x, y, z):
print x, y, z
def b(x, y, z='fruitbat')
print x, y, z

for func in a, b:
def wrapper(func=func, *args, **argsk):
# do something
func(*args, **argsk)
x.append(wrapper)

x[0](1, 2, 3)
x[1](1, 2)
....

Is there any way to do this? Can you capture arguments in a tuple and dict,
but still receive other keyword arguments? The only solution I found was to
implement wrapper as a class (like I would in c++):

class wrapper(object):
def __init__(self, func):
self.func = func
def __call__(self, *args, **argsk):
self.func(*args, **argsk)

Jeremy

--
Jeremy Sanders
http://www.jeremysanders.net/

[Ryan Ginstrom]

On Behalf Of Jeremy Sanders

def a(x, y, z):
print x, y, z
def b(x, y, z='fruitbat')
print x, y, z

for func in a, b:
def wrapper(func=func, *args, **argsk):
# do something
func(*args, **argsk)
x.append(wrapper)

x[0](1, 2, 3)
x[1](1, 2)
...

Is there any way to do this? Can you capture arguments in a
tuple and dict, but still receive other keyword arguments?

I think you're missing one level of wrapping.

>>def a(x, y, z):

print x, y, z

>>def b(x, y, z='fruitbat'):

print x, y, z

>>x = []
for func in a, b:

def wrapper(func):
def wrapped(*args, **kwds):
print "wrapped!"
func(*args, **kwds)
return wrapped
x.append(wrapper(func))

>>x[0](1, 2, 3)

wrapped!
1 2 3

>>x[1](1, 2)

wrapped!
1 2 fruitbat

>>>

---
Regards,
Ryan Ginstrom