Passing a tuple to a function as multiple arguments

[Ben Warren]

Hello,

Let's say I have a function with a variable number of arguments(please ignore syntax errors):

def myfunc(a,b,c,d,...):

and I have a tuple whose contents I want to pass to the function. The number of elements in the tuple will not always be the same.

T = A,B,C,D,...

Is there a way that I can pass the contents of the tuple to the functionwithout explicitly indexing the elements? Something like:

myfunc(magic(T))

where magic() expands the tuple to its multiple elements. I'vetried various for loop constructs, but everything I can think of returns alist, which doesn't work because it's viewed as one parameter.
thanks,
Ben

[George Sakkis]

On Sep 6, 11:02 pm, Ben Warren <[e-mail]:

Hello,

Let's say I have a function with a variable number of arguments (please ignore syntax errors):

def myfunc(a,b,c,d,...):

and I have a tuple whose contents I want to pass to the function. The number of elements in the tuple will not always be the same.

T = A,B,C,D,...

Is there a way that I can pass the contents of the tuple to the function without explicitly indexing the elements?

Yes:

myfunc(*T)

More details at http://docs.python.org/tut/node6.htm...00000000000000
HTH,
George