return dictionary values as single list

kdt

Can anyone suggest a better way of returning the values in a dictionary as a single list. I have the following, but it uses a nested loop, not sure if there is a more efficient way.

thanks

Aug 15 '07 #1

ilikepython

Can anyone suggest a better way of returning the values in a dictionary as a single list. I have the following, but it uses a nested loop, not sure if there is a more efficient way.

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1. >>> d['a']= [(45,6)]
2. >>> d['a'].append((56,4))
3. >>> d['a']
4. [(45, 6), (56, 4)]
5. >>> s =[]
6. >>> for i, j in enumerate(d['a']):
7. ...     for k, l in enumerate(j):
8. ...         s.append(l)
9. ...         
10. >>> s
11. [45, 6, 56, 4]
12. >>> 
13.  

thanks

Hope that helps.

Aug 15 '07 #2

bartonc

Can anyone suggest a better way of returning the values in a dictionary as a single list. I have the following, but it uses a nested loop, not sure if there is a more efficient way.

Expand|Select|Wrap|Line Numbers

1. >>> d['a']= [(45,6)]
2. >>> d['a'].append((56,4))
3. >>> d['a']
4. [(45, 6), (56, 4)]
5. >>> s =[]
6. >>> for i, j in enumerate(d['a']):
7. ...     for k, l in enumerate(j):
8. ...         s.append(l)
9. ...         
10. >>> s
11. [45, 6, 56, 4]
12. >>> 
13.  

thanks

Aug 15 '07 #3

kdt

Sweet, thanks. Much better!

Aug 15 '07 #4

bartonc

Sweet, thanks. Much better!

You did see mine, right? One minute apart, maybe you were posting while I was.

Aug 15 '07 #5

ilikepython

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1. >>> aList = [(45, 6), (56, 4)]
2. >>> newList = []
3. >>> for tup in aList:
4. ...     newList.extend(tup)
5. ...     
6. >>> newList
7. [45, 6, 56, 4]
8. >>> 

Just for fun, you could do that with map:

Aug 15 '07 #6

bartonc

Just for fun, you could do that with map:

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1. >>> aList = [(45, 6), (56, 4)]
2. >>> newList = []
3. >>> map(newList.extend, aList)
4. >>> newList
5. [45, 6, 56, 4]
6.  

Bonus points to you, my friend! Two lines in one; very nicely done.

Aug 15 '07 #7