return dictionary values as single list

[kdt]

Can anyone suggest a better way of returning the values in a dictionary as a single list. I have the following, but it uses a nested loop, not sure if there is a more efficient way.

>>> d['a']= [(45,6)]
>>> d['a'].append((56,4))
>>> d['a']
[(45, 6), (56, 4)]
>>> s =[]
>>> for i, j in enumerate(d['a']):
...     for k, l in enumerate(j):
...         s.append(l)
...         
>>> s
[45, 6, 56, 4]
>>> 
 

thanks

[ilikepython]

Can anyone suggest a better way of returning the values in a dictionary as a single list. I have the following, but it uses a nested loop, not sure if there is a more efficient way.

>>> d['a']= [(45,6)]
>>> d['a'].append((56,4))
>>> d['a']
[(45, 6), (56, 4)]
>>> s =[]
>>> for i, j in enumerate(d['a']):
...     for k, l in enumerate(j):
...         s.append(l)
...         
>>> s
[45, 6, 56, 4]
>>> 
 

thanks

s = [value for tup in d['a'] for value in tup]
 

Hope that helps.

[bartonc]

Can anyone suggest a better way of returning the values in a dictionary as a single list. I have the following, but it uses a nested loop, not sure if there is a more efficient way.

>>> d['a']= [(45,6)]
>>> d['a'].append((56,4))
>>> d['a']
[(45, 6), (56, 4)]
>>> s =[]
>>> for i, j in enumerate(d['a']):
...     for k, l in enumerate(j):
...         s.append(l)
...         
>>> s
[45, 6, 56, 4]
>>> 
 

thanks

>>> aList = [(45, 6), (56, 4)]
>>> newList = []
>>> for tup in aList:
...     newList.extend(tup)
...     
>>> newList
[45, 6, 56, 4]
>>> 

[kdt]

Sweet, thanks. Much better!

[bartonc]

Sweet, thanks. Much better!

You did see mine, right? One minute apart, maybe you were posting while I was.

[ilikepython]

>>> aList = [(45, 6), (56, 4)]
>>> newList = []
>>> for tup in aList:
...     newList.extend(tup)
...     
>>> newList
[45, 6, 56, 4]
>>> 

Just for fun, you could do that with map:

>>> aList = [(45, 6), (56, 4)]
>>> newList = []
>>> map(newList.extend, aList)
>>> newList
[45, 6, 56, 4]
 

[bartonc]

Just for fun, you could do that with map:

>>> aList = [(45, 6), (56, 4)]
>>> newList = []
>>> map(newList.extend, aList)
>>> newList
[45, 6, 56, 4]
 

Bonus points to you, my friend! Two lines in one; very nicely done.