searching within a file

[LolaT]

Does anyone know where I can read up on how to search for a particular object in a file? For example, search for a particular word in a dictionary?

[linksterman]

file("file name.txt", 'rb')
fil.find("word")

[bvdet]

Not much to it really:

>>> f = open(r'C:\SDS2_7.0\jobs\60801_Baylor\macro\DeepEllumRad1.txt')
>>> for line in f:
...     if 'Deep Ellum' in line:
...         print line
...         
# Deep Ellum radii and cons lines at Canopy 1 (B-D)
 
>>> f.close()
>>> 

Do you have a specific problem you are trying to solve?

[LolaT]

Not much to it really:

>>> f = open(r'C:\SDS2_7.0\jobs\60801_Baylor\macro\DeepEllumRad1.txt')
>>> for line in f:
...     if 'Deep Ellum' in line:
...         print line
...         
# Deep Ellum radii and cons lines at Canopy 1 (B-D)
 
>>> f.close()
>>> 

Do you have a specific problem you are trying to solve?

Thanks for the advice.
I'm trying to create a spell checker which can spell check either a single word or a file depending on what the user chooses. The spell checker is really simple though, it doesn't point out a word that is spelled wrong, however it checks two different files to see if the word(s) is/are typed in are contained in either file. One of the files is a dictionary file with a list of words, and the other file is the user dictionary, created by the user.

[bvdet]

Thanks for the advice.
I'm trying to create a spell checker which can spell check either a single word or a file depending on what the user chooses. The spell checker is really simple though, it doesn't point out a word that is spelled wrong, however it checks two different files to see if the word(s) is/are typed in are contained in either file. One of the files is a dictionary file with a list of words, and the other file is the user dictionary, created by the user.

You are welcome. Let us know how the project goes for you.

[anonymous]

import re
authorpattern = "<meta name="AUTHOR" content="(.*?)"><meta name="
patt = re.compile(authorpattern,re.IGNORECASE)
 
authors = re.findall(patt,data)
 
or if you need only 1 author
 
amatch = re.search(source.authorpattern,data,re.IGNORECASE)
author = amatch.group(1)

[bartonc]

import re
authorpattern = "<meta name="AUTHOR" content="(.*?)"><meta name="
patt = re.compile(authorpattern,re.IGNORECASE)
 
authors = re.findall(patt,data)
 
or if you need only 1 author
 
amatch = re.search(source.authorpattern,data,re.IGNORECASE)
author = amatch.group(1)

Hello, annonymous! I'm impressed: 49 posts; C++, Java, MySQL, now Python and a regex to boot.

I welcome your contributions here in the Python forum. I must, however, that you use [code] tags any time that you post executable lines. And

# Adding =python to them makes them look even better.

Thank you.

[LolaT]

thanks again to everyone for their help.
i'm encountering a major problem with my project though.
i'm supposed to take the file named dict.txt which has quite the amount of words
and turn it into a list.
i know how to do it (at least i think so) but my program keeps shutting down, i'm guessing because the file is pretty large.
any suggestions?