search and replace

[ironmonkey69]

is there a way that I can search for every nth term sucha as a number ranging from 0-2500 and replacing them with zeroes?

[bvdet]

is there a way that I can search for every nth term sucha as a number ranging from 0-2500 and replacing them with zeroes?

In a list of numbers in sequence:

>>> def nthzero(numList, nth):
...     outList = []
...     for num in numList:
...         if not num%nth:
...             outList.append(0)
...         else:
...             outList.append(num)
...     return outList
... 
>>> nthzero(range(1,50),7)
[1, 2, 3, 4, 5, 6, 0, 8, 9, 10, 11, 12, 13, 0, 15, 16, 17, 18, 19, 20, 0, 22, 23, 24, 25, 26, 27, 0, 29, 30, 31, 32, 33, 34, 0, 36, 37, 38, 39, 40, 41, 0, 43, 44, 45, 46, 47, 48, 0]
>>> 

OR any list:

def nthzero(numList, nth):
    outList = []
    for i, num in enumerate(numList):
        if not (i+1)%nth:
            outList.append(0)
        else:
            outList.append(num)
    return outList
 
 
numList = range(6,400,12)
nth = 7
 
print nthzero(numList, nth)
print nthzero(['x']*30, nth)
 
>>> [6, 18, 30, 42, 54, 66, 0, 90, 102, 114, 126, 138, 150, 0, 174, 186, 198, 210, 222, 234, 0, 258, 270, 282, 294, 306, 318, 0, 342, 354, 366, 378, 390]
['x', 'x', 'x', 'x', 'x', 'x', 0, 'x', 'x', 'x', 'x', 'x', 'x', 0, 'x', 'x', 'x', 'x', 'x', 'x', 0, 'x', 'x', 'x', 'x', 'x', 'x', 0, 'x', 'x']
>>>

[ironmonkey69]

what can I do if the numbers are not separated by commas?

[bartonc]

what can I do if the numbers are not separated by commas?

Your question lacks specificity. Perhaps you are wanting to work with text?
Maybe that text is broken up with newline character, maybe not.
You may even need help reading a text file into memory.

Please be specific in your questions.
Thank you.

[cnobile]

You can use a for loop like this.

numbers = range(0,2500) # Make list of numbers
step = 5
 
for num in range(numbers[0], numbers[-1], step):
    numbers[num] = 0 # set to zero
 
print numbers
 

This will work with text or numbers. First put your objects in a list. In the case of text use 0 instead of numbers[0] and the result of len(text) for numbers[-1].