Hi!
My code is
db = {}
def display():
keyList = db.keys()
sortedList = keyList.sort()
for name in sortedList:
line = 'Name: %s, Number: %s' % (name, db[name])
print line.replace('\r', '')
And it gives following error:
for name in sortedList:
TypeError: 'NoneType' object is not iterable
How can sortedList variable turn into NoneType? I just don't get it... 5 15579 to*@finland.com schrieb:
Hi!
My code is
db = {}
>
>def display(): keyList = db.keys() sortedList = keyList.sort() for name in sortedList: line = 'Name: %s, Number: %s' % (name, db[name]) print line.replace('\r', '')
And it gives following error:
> for name in sortedList: TypeError: 'NoneType' object is not iterable
How can sortedList variable turn into NoneType? I just don't get it...
It does not turn into something. The `sort()` method just works "in
place", i. e. it will mutate the list it has been called with. It
returns None (because there is no other sensible return value).
For you, that means: You don't have to distinguish between keyList and
sortedList. Just call ``.sort()`` on keyList and it will just work.
HTH,
Stargaming
P.S. same information is in the docs: http://docs.python.org/lib/typesseq-mutable.html
On Fri, 13 Jul 2007 20:44:13 +0300, <to*@finland.comwrote:
>
Hi!
My code is
db = {}
> def display(): keyList = db.keys() sortedList = keyList.sort() for name in sortedList: line = 'Name: %s, Number: %s' % (name, db[name]) print line.replace('\r', '')
And it gives following error:
> for name in sortedList: TypeError: 'NoneType' object is not iterable
How can sortedList variable turn into NoneType? I just don't get it...
db is out of scope, you have to pass it to the function:
>def display(db): keyList = db.keys() sortedList = keyList.sort() for name in sortedList: line = 'Name: %s, Number: %s' % (name, db[name]) print line.replace('\r', '')
--
Using Opera's revolutionary e-mail client: http://www.opera.com/mail/
Daniel wrote:
db is out of scope, you have to pass it to the function:
What's wrong about module attributes?
Regards,
Björn
--
BOFH excuse #418:
Sysadmins busy fighting SPAM.
On Fri, 13 Jul 2007 21:13:20 +0300, Bjoern Schliessmann
<us**************************@spamgourmet.comwrote :
>
Daniel wrote:
>db is out of scope, you have to pass it to the function:
What's wrong about module attributes?
I made a mistake
Stargaming <st********@gmail.comwrites:
It does not turn into something. The `sort()` method just works "in
place", i. e. it will mutate the list it has been called with. It
returns None (because there is no other sensible return value).
For you, that means: You don't have to distinguish between keyList and
sortedList. Just call ``.sort()`` on keyList and it will just work.
Alternatively, use
sortedList = sorted(keyList) This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics
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