for example, let
from operator import itemgetter
items = [('a', [5, 2]), ('c', [1]), ('b', [6]), ('d', [7])]
sorted(items, key = itemgetter(1))
get this back:
[('c', [1]), ('a', [5, 2]), ('b', [6]), ('d', [7])]
but
sorted(items, key = sum(itemgetter(1)))
raise a errer:
'operator.itemgetter' object is not iterable
how to sorted by summed itemgetter(1)?
maybe sorted(items,key = lambda x:sum(x[1]))
can't itemgetter be used here? 2 2002
Aldarion <Er*************@gmail.comwrites:
how to sorted by summed itemgetter(1)?
maybe sorted(items,key = lambda x:sum(x[1]))
can't itemgetter be used here?
You really want function composition, e.g.
sorted(items, key=sum*itemgetter(1))
where * is a composition operator (doesn't exist in Python).
You could write:
def compose(f,g):
return lambda *a,**k: f(g(*a,**k))
and then use
sorted(items, key=compose(sum,itemgetter(1)))
or spell it out inline:
sorted(items, key=lambda x: sum(itemgetter(1)(x)))
I'd probably do something like:
snd = itemgetter(1) # I use this all the time
sorted(items, key=lambda x: sum(snd(x)))
Thanks for the reply,I got it.
On 6 25 , 9 19 , Paul Rubin <http://phr...@NOSPAM.invalidwrote:
Aldarion <ErendisAldar...@gmail.comwrites:
how to sorted by summed itemgetter(1)?
maybe sorted(items,key = lambda x:sum(x[1]))
can't itemgetter be used here?
You really want function composition, e.g.
sorted(items, key=sum*itemgetter(1))
where * is a composition operator (doesn't exist in Python).
You could write:
def compose(f,g):
return lambda *a,**k: f(g(*a,**k))
and then use
sorted(items, key=compose(sum,itemgetter(1)))
or spell it out inline:
sorted(items, key=lambda x: sum(itemgetter(1)(x)))
I'd probably do something like:
snd = itemgetter(1) # I use this all the time
sorted(items, key=lambda x: sum(snd(x)))
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