add a line to a file and then automatically rename it

[halcon]

Hi,
What if I want to add a line to a file and then automatically rename it in a cycle using a sequence of numbers. I mean, if the original file has the name file0.txt then the next file should be file1.txt and the next should be file2.txt and so on.

I hope you can give me some help here.

Thanks

[ghostdog74]

Hi,
What if I want to add a line to a file and then automatically rename it in a cycle using a sequence of numbers. I mean, if the original file has the name file0.txt then the next file should be file1.txt and the next should be file2.txt and so on.

I hope you can give me some help here.

Thanks

not tested...

import os,shutil
if os.path.exists("num"):
     value=open("num").read().strip()
lineToAdd = "new line"
newfile ="file%s.txt" % str(int(num)+1)
shutil.copy("file0.txt",  newfile)
open(newfile,"a").write(line+"\n")
 

[bvdet]

Hi,
What if I want to add a line to a file and then automatically rename it in a cycle using a sequence of numbers. I mean, if the original file has the name file0.txt then the next file should be file1.txt and the next should be file2.txt and so on.

I hope you can give me some help here.

Thanks

import os, re
 
patt = r'\d+\Z'
 
# seed file, name must end with one or more digits
fn = r'X:\directory\subdir\name999.txt'
 
for i in range(5):
    fnList = list(os.path.splitext(fn))
 
    num = re.search(patt, fnList[0]).group(0)
    fnList[0] = re.sub(patt, str(int(num)+1), fnList[0])
 
    stringToAdd = '9876543210'
 
    fn1 = ''.join(fnList)
    f = open(fn1, 'w')
    f.write('%s\n%s' % (open(fn).read(), stringToAdd))
    f.close()
    fn = fn1