Hi,
I have two dictionaries
dict1={'B8': set(['I8', 'H8', 'B2', 'B7', 'F8', 'C9', 'G8', 'B4',
'B5', 'B6', 'C8', 'E8', 'D8', 'B3', 'A9', 'A8', 'C7', 'B9', 'A7',
'B1']), 'B9': set(['I9', 'H9', 'A7', 'F9', 'B3', 'B6', 'G9', 'B4',
'B5', 'C9', 'B7', 'E9', 'B1', 'B2', 'D9', 'A9', 'A8', 'C8', 'B8',
'C7']), 'D1': set(['F1', 'F2', 'F3', 'G1', 'I1', 'D2', 'H1', 'A1',
'D4', 'B1', 'D8', 'D9', 'D6', 'D7', 'C1', 'D5', 'E1', 'D3', 'E3',
'E2'])}
and
dict2=
{'I6': '0', 'H9': '9', 'I2': '0', 'E8': '0', 'H3': '0', 'H7': '0',
'I7': '3', 'I4': '0', 'H5': '0', 'F9': '0', 'G7': '5', 'G6': '9',
'G5': '0', 'E1': '7', 'G3': '2', 'G2': '0', 'G1': '0', 'I1': '0',
'C8': '0', 'I3': '5', 'E5': '0', 'I5': '1', 'C9': '0', 'G9': '0',
'G8': '0', 'A1': '0', 'A3': '3', 'A2': '0', 'A5': '2', 'A4': '0',
'A7': '6', 'A6': '0', 'C3': '1', 'C2': '0', 'C1': '0', 'E6': '0',
'C7': '4', 'C6': '6', 'C5': '0', 'C4': '8', 'I9': '0', 'D8': '0',
'I8': '0', 'E4': '0', 'D9': '0', 'H8': '0', 'F6': '8', 'A9': '0',
'G4': '6', 'A8': '0', 'E7': '0', 'E3': '0', 'F1': '0', 'F2': '0',
'F3': '6', 'F4': '7', 'F5': '0', 'E2': '0', 'F7': '2', 'F8': '0',
'D2': '0', 'H1': '8', 'H6': '3', 'H2': '0', 'H4': '2', 'D3': '8',
'B4': '3', 'B5': '0', 'B6': '5', 'B7': '0', 'E9': '8', 'B1': '9',
'B2': '0', 'B3': '0', 'D6': '2', 'D7': '9', 'D4': '1', 'D5': '0',
'B8': '0', 'B9': '1', 'D1': '0'}
Now I want to create a dict which would have both the keys and values
to be of the corresponding values of dict2.
Something like this:
Eg. The first key in dict1 i.e. B8 as 0 (0 is the value of B8 in
dict2) mapped as set(['0','0','0',...]).
Can anyone help me out with this.

Anush 8 1284
En Mon, 11 Jun 2007 17:24:26 0300, anush shetty
<it************@gmail.comescribió:
Hi,
I have two dictionaries
dict1={'B8': set(['I8', 'H8', 'B2', 'B7', 'F8', 'C9', 'G8', 'B4',
'B5', 'B6', 'C8', 'E8', 'D8', 'B3', 'A9', 'A8', 'C7', 'B9', 'A7',
'B1']), 'B9': set(['I9', 'H9', 'A7', 'F9', 'B3', 'B6', 'G9', 'B4',
'B5', 'C9', 'B7', 'E9', 'B1', 'B2', 'D9', 'A9', 'A8', 'C8', 'B8',
'C7']), ...
and
dict2=
{'I6': '0', 'H9': '9', 'I2': '0', 'E8': '0', 'H3': '0', 'H7': '0',
'I7': '3', 'I4': '0', 'H5': '0', 'F9': '0', 'G7': '5', 'G6': '9', [...]
'B2': '0', 'B3': '0', 'D6': '2', 'D7': '9', 'D4': '1', 'D5': '0',
'B8': '0', 'B9': '1', 'D1': '0'}
Now I want to create a dict which would have both the keys and values
to be of the corresponding values of dict2.
Something like this:
Eg. The first key in dict1 i.e. B8 as 0 (0 is the value of B8 in
dict2) mapped as set(['0','0','0',...]).
Sets can't have duplicate elements, so set(['0','0','0'])==set(['0'])
And dictionaries can't have duplicate keys either.
What do you want to do exactly? How would your desired structure look like?

Gabriel Genellina
anush shetty wrote:
Hi,
I have two dictionaries
dict1={'B8': set(['I8', 'H8', 'B2', 'B7', 'F8', 'C9', 'G8', 'B4',
'B5', 'B6', 'C8', 'E8', 'D8', 'B3', 'A9', 'A8', 'C7', 'B9', 'A7',
'B1']), 'B9': set(['I9', 'H9', 'A7', 'F9', 'B3', 'B6', 'G9', 'B4',
'B5', 'C9', 'B7', 'E9', 'B1', 'B2', 'D9', 'A9', 'A8', 'C8', 'B8',
'C7']), 'D1': set(['F1', 'F2', 'F3', 'G1', 'I1', 'D2', 'H1', 'A1',
'D4', 'B1', 'D8', 'D9', 'D6', 'D7', 'C1', 'D5', 'E1', 'D3', 'E3',
'E2'])}
and
dict2=
{'I6': '0', 'H9': '9', 'I2': '0', 'E8': '0', 'H3': '0', 'H7': '0',
'I7': '3', 'I4': '0', 'H5': '0', 'F9': '0', 'G7': '5', 'G6': '9',
'G5': '0', 'E1': '7', 'G3': '2', 'G2': '0', 'G1': '0', 'I1': '0',
'C8': '0', 'I3': '5', 'E5': '0', 'I5': '1', 'C9': '0', 'G9': '0',
'G8': '0', 'A1': '0', 'A3': '3', 'A2': '0', 'A5': '2', 'A4': '0',
'A7': '6', 'A6': '0', 'C3': '1', 'C2': '0', 'C1': '0', 'E6': '0',
'C7': '4', 'C6': '6', 'C5': '0', 'C4': '8', 'I9': '0', 'D8': '0',
'I8': '0', 'E4': '0', 'D9': '0', 'H8': '0', 'F6': '8', 'A9': '0',
'G4': '6', 'A8': '0', 'E7': '0', 'E3': '0', 'F1': '0', 'F2': '0',
'F3': '6', 'F4': '7', 'F5': '0', 'E2': '0', 'F7': '2', 'F8': '0',
'D2': '0', 'H1': '8', 'H6': '3', 'H2': '0', 'H4': '2', 'D3': '8',
'B4': '3', 'B5': '0', 'B6': '5', 'B7': '0', 'E9': '8', 'B1': '9',
'B2': '0', 'B3': '0', 'D6': '2', 'D7': '9', 'D4': '1', 'D5': '0',
'B8': '0', 'B9': '1', 'D1': '0'}
Now I want to create a dict which would have both the keys and values
to be of the corresponding values of dict2.
Something like this:
Eg. The first key in dict1 i.e. B8 as 0 (0 is the value of B8 in
dict2) mapped as set(['0','0','0',...]).
Can anyone help me out with this.

Anush
new_dict = {}
for akey, aset in dict1.items():
new_dict[akey] = sum(int(dict2[k]) for k in aset)
James
On Jun 12, 2:10 am, James Stroud <jstr...@mbi.ucla.eduwrote:
anush shetty wrote:
Hi,
I have two dictionaries
dict1={'B8': set(['I8', 'H8', 'B2', 'B7', 'F8', 'C9', 'G8', 'B4',
'B5', 'B6', 'C8', 'E8', 'D8', 'B3', 'A9', 'A8', 'C7', 'B9', 'A7',
'B1']), 'B9': set(['I9', 'H9', 'A7', 'F9', 'B3', 'B6', 'G9', 'B4',
'B5', 'C9', 'B7', 'E9', 'B1', 'B2', 'D9', 'A9', 'A8', 'C8', 'B8',
'C7']), 'D1': set(['F1', 'F2', 'F3', 'G1', 'I1', 'D2', 'H1', 'A1',
'D4', 'B1', 'D8', 'D9', 'D6', 'D7', 'C1', 'D5', 'E1', 'D3', 'E3',
'E2'])}
and
dict2=
{'I6': '0', 'H9': '9', 'I2': '0', 'E8': '0', 'H3': '0', 'H7': '0',
'I7': '3', 'I4': '0', 'H5': '0', 'F9': '0', 'G7': '5', 'G6': '9',
'G5': '0', 'E1': '7', 'G3': '2', 'G2': '0', 'G1': '0', 'I1': '0',
'C8': '0', 'I3': '5', 'E5': '0', 'I5': '1', 'C9': '0', 'G9': '0',
'G8': '0', 'A1': '0', 'A3': '3', 'A2': '0', 'A5': '2', 'A4': '0',
'A7': '6', 'A6': '0', 'C3': '1', 'C2': '0', 'C1': '0', 'E6': '0',
'C7': '4', 'C6': '6', 'C5': '0', 'C4': '8', 'I9': '0', 'D8': '0',
'I8': '0', 'E4': '0', 'D9': '0', 'H8': '0', 'F6': '8', 'A9': '0',
'G4': '6', 'A8': '0', 'E7': '0', 'E3': '0', 'F1': '0', 'F2': '0',
'F3': '6', 'F4': '7', 'F5': '0', 'E2': '0', 'F7': '2', 'F8': '0',
'D2': '0', 'H1': '8', 'H6': '3', 'H2': '0', 'H4': '2', 'D3': '8',
'B4': '3', 'B5': '0', 'B6': '5', 'B7': '0', 'E9': '8', 'B1': '9',
'B2': '0', 'B3': '0', 'D6': '2', 'D7': '9', 'D4': '1', 'D5': '0',
'B8': '0', 'B9': '1', 'D1': '0'}
Now I want to create a dict which would have both the keys and values
to be of the corresponding values of dict2.
Something like this:
Eg. The first key in dict1 i.e. B8 as 0 (0 is the value of B8 in
dict2) mapped as set(['0','0','0',...]).
Can anyone help me out with this.

Anush
new_dict = {}
for akey, aset in dict1.items():
new_dict[akey] = sum(int(dict2[k]) for k in aset)
James
So there is no way I can represent all the duplicates right.
So is there any solution where I could take the values of dictionary
and represent them separately?

Anush
On Jun 12, 1:50 am, "Gabriel Genellina" <gagsl...@yahoo.com.ar>
wrote:
En Mon, 11 Jun 2007 17:24:26 0300, anush shetty
<itsanushshe...@gmail.comescribió:
Hi,
I have two dictionaries
dict1={'B8': set(['I8', 'H8', 'B2', 'B7', 'F8', 'C9', 'G8', 'B4',
'B5', 'B6', 'C8', 'E8', 'D8', 'B3', 'A9', 'A8', 'C7', 'B9', 'A7',
'B1']), 'B9': set(['I9', 'H9', 'A7', 'F9', 'B3', 'B6', 'G9', 'B4',
'B5', 'C9', 'B7', 'E9', 'B1', 'B2', 'D9', 'A9', 'A8', 'C8', 'B8',
'C7']), ...
and
dict2=
{'I6': '0', 'H9': '9', 'I2': '0', 'E8': '0', 'H3': '0', 'H7': '0',
'I7': '3', 'I4': '0', 'H5': '0', 'F9': '0', 'G7': '5', 'G6': '9', [...]
'B2': '0', 'B3': '0', 'D6': '2', 'D7': '9', 'D4': '1', 'D5': '0',
'B8': '0', 'B9': '1', 'D1': '0'}
Now I want to create a dict which would have both the keys and values
to be of the corresponding values of dict2.
Something like this:
Eg. The first key in dict1 i.e. B8 as 0 (0 is the value of B8 in
dict2) mapped as set(['0','0','0',...]).
Sets can't have duplicate elements, so set(['0','0','0'])==set(['0'])
And dictionaries can't have duplicate keys either.
What do you want to do exactly? How would your desired structure look like?

Gabriel Genellina
Need it for a verification of the puzzle. It has duplicate values. But
there is any way where i could represent them with duplicates

Anush
On Jun 11, 10:19 pm, anush shetty <itsanushshe...@gmail.comwrote:
On Jun 12, 2:10 am, James Stroud <jstr...@mbi.ucla.eduwrote:
anush shetty wrote:
Hi,
I have two dictionaries
dict1={'B8': set(['I8', 'H8', 'B2', 'B7', 'F8', 'C9', 'G8', 'B4',
'B5', 'B6', 'C8', 'E8', 'D8', 'B3', 'A9', 'A8', 'C7', 'B9', 'A7',
'B1']), 'B9': set(['I9', 'H9', 'A7', 'F9', 'B3', 'B6', 'G9', 'B4',
'B5', 'C9', 'B7', 'E9', 'B1', 'B2', 'D9', 'A9', 'A8', 'C8', 'B8',
'C7']), 'D1': set(['F1', 'F2', 'F3', 'G1', 'I1', 'D2', 'H1', 'A1',
'D4', 'B1', 'D8', 'D9', 'D6', 'D7', 'C1', 'D5', 'E1', 'D3', 'E3',
'E2'])}
and
dict2=
{'I6': '0', 'H9': '9', 'I2': '0', 'E8': '0', 'H3': '0', 'H7': '0',
'I7': '3', 'I4': '0', 'H5': '0', 'F9': '0', 'G7': '5', 'G6': '9',
'G5': '0', 'E1': '7', 'G3': '2', 'G2': '0', 'G1': '0', 'I1': '0',
'C8': '0', 'I3': '5', 'E5': '0', 'I5': '1', 'C9': '0', 'G9': '0',
'G8': '0', 'A1': '0', 'A3': '3', 'A2': '0', 'A5': '2', 'A4': '0',
'A7': '6', 'A6': '0', 'C3': '1', 'C2': '0', 'C1': '0', 'E6': '0',
'C7': '4', 'C6': '6', 'C5': '0', 'C4': '8', 'I9': '0', 'D8': '0',
'I8': '0', 'E4': '0', 'D9': '0', 'H8': '0', 'F6': '8', 'A9': '0',
'G4': '6', 'A8': '0', 'E7': '0', 'E3': '0', 'F1': '0', 'F2': '0',
'F3': '6', 'F4': '7', 'F5': '0', 'E2': '0', 'F7': '2', 'F8': '0',
'D2': '0', 'H1': '8', 'H6': '3', 'H2': '0', 'H4': '2', 'D3': '8',
'B4': '3', 'B5': '0', 'B6': '5', 'B7': '0', 'E9': '8', 'B1': '9',
'B2': '0', 'B3': '0', 'D6': '2', 'D7': '9', 'D4': '1', 'D5': '0',
'B8': '0', 'B9': '1', 'D1': '0'}
Now I want to create a dict which would have both the keys and values
to be of the corresponding values of dict2.
Something like this:
Eg. The first key in dict1 i.e. B8 as 0 (0 is the value of B8 in
dict2) mapped as set(['0','0','0',...]).
Can anyone help me out with this.

Anush
new_dict = {}
for akey, aset in dict1.items():
new_dict[akey] = sum(int(dict2[k]) for k in aset)
James
So there is no way I can represent all the duplicates right.
So is there any solution where I could take the values of dictionary
and represent them separately?

Anush
I use lists instead of your dict1 but preserve your mapping dict2:
data = [
['B8',
['I8', 'H8', 'B2', 'B7', 'F8',
'C9', 'G8', 'B4', 'B5', 'B6',
'C8', 'E8', 'D8', 'B3', 'A9',
'A8', 'C7', 'B9', 'A7', 'B1']],
['B9',
['I9', 'H9', 'A7', 'F9', 'B3',
'B6', 'G9', 'B4', 'B5', 'C9',
'B7', 'E9', 'B1', 'B2', 'D9',
'A9', 'A8', 'C8', 'B8', 'C7']],
['D1',
['F1', 'F2', 'F3', 'G1', 'I1',
'D2', 'H1', 'A1', 'D4', 'B1',
'D8', 'D9', 'D6', 'D7', 'C1',
'D5', 'E1', 'D3', 'E3', 'E2']]]
dict2= {
'I6': '0', 'H9': '9', 'I2': '0', 'E8': '0', 'H3': '0', 'H7': '0',
'I7': '3', 'I4': '0', 'H5': '0', 'F9': '0', 'G7': '5', 'G6': '9',
'G5': '0', 'E1': '7', 'G3': '2', 'G2': '0', 'G1': '0', 'I1': '0',
'C8': '0', 'I3': '5', 'E5': '0', 'I5': '1', 'C9': '0', 'G9': '0',
'G8': '0', 'A1': '0', 'A3': '3', 'A2': '0', 'A5': '2', 'A4': '0',
'A7': '6', 'A6': '0', 'C3': '1', 'C2': '0', 'C1': '0', 'E6': '0',
'C7': '4', 'C6': '6', 'C5': '0', 'C4': '8', 'I9': '0', 'D8': '0',
'I8': '0', 'E4': '0', 'D9': '0', 'H8': '0', 'F6': '8', 'A9': '0',
'G4': '6', 'A8': '0', 'E7': '0', 'E3': '0', 'F1': '0', 'F2': '0',
'F3': '6', 'F4': '7', 'F5': '0', 'E2': '0', 'F7': '2', 'F8': '0',
'D2': '0', 'H1': '8', 'H6': '3', 'H2': '0', 'H4': '2', 'D3': '8',
'B4': '3', 'B5': '0', 'B6': '5', 'B7': '0', 'E9': '8', 'B1': '9',
'B2': '0', 'B3': '0', 'D6': '2', 'D7': '9', 'D4': '1', 'D5': '0',
'B8': '0', 'B9': '1', 'D1': '0'}
dout = [[dict2[i],[dict2[k] for k in j]]
for i,j in data]
print dout
 Paddy.
>
dout = [[dict2[i],[dict2[k] for k in j]]
for i,j in data]
print dout
 Paddy.
Working from your original dict1:
dout = [[dict2[i], [dict2[k] for k in setvalue]]
for i,setvalue in dict1.iteritems()]
 Paddy
anush shetty wrote:
On Jun 12, 2:10 am, James Stroud <jstr...@mbi.ucla.eduwrote:
>>anush shetty wrote:
>>>Hi, I have two dictionaries
>>dict1={'B8': set(['I8', 'H8', 'B2', 'B7', 'F8', 'C9', 'G8', 'B4', 'B5', 'B6', 'C8', 'E8', 'D8', 'B3', 'A9', 'A8', 'C7', 'B9', 'A7', 'B1']), 'B9': set(['I9', 'H9', 'A7', 'F9', 'B3', 'B6', 'G9', 'B4', 'B5', 'C9', 'B7', 'E9', 'B1', 'B2', 'D9', 'A9', 'A8', 'C8', 'B8', 'C7']), 'D1': set(['F1', 'F2', 'F3', 'G1', 'I1', 'D2', 'H1', 'A1', 'D4', 'B1', 'D8', 'D9', 'D6', 'D7', 'C1', 'D5', 'E1', 'D3', 'E3', 'E2'])}
>>>and dict2= {'I6': '0', 'H9': '9', 'I2': '0', 'E8': '0', 'H3': '0', 'H7': '0', 'I7': '3', 'I4': '0', 'H5': '0', 'F9': '0', 'G7': '5', 'G6': '9', 'G5': '0', 'E1': '7', 'G3': '2', 'G2': '0', 'G1': '0', 'I1': '0', 'C8': '0', 'I3': '5', 'E5': '0', 'I5': '1', 'C9': '0', 'G9': '0', 'G8': '0', 'A1': '0', 'A3': '3', 'A2': '0', 'A5': '2', 'A4': '0', 'A7': '6', 'A6': '0', 'C3': '1', 'C2': '0', 'C1': '0', 'E6': '0', 'C7': '4', 'C6': '6', 'C5': '0', 'C4': '8', 'I9': '0', 'D8': '0', 'I8': '0', 'E4': '0', 'D9': '0', 'H8': '0', 'F6': '8', 'A9': '0', 'G4': '6', 'A8': '0', 'E7': '0', 'E3': '0', 'F1': '0', 'F2': '0', 'F3': '6', 'F4': '7', 'F5': '0', 'E2': '0', 'F7': '2', 'F8': '0', 'D2': '0', 'H1': '8', 'H6': '3', 'H2': '0', 'H4': '2', 'D3': '8', 'B4': '3', 'B5': '0', 'B6': '5', 'B7': '0', 'E9': '8', 'B1': '9', 'B2': '0', 'B3': '0', 'D6': '2', 'D7': '9', 'D4': '1', 'D5': '0', 'B8': '0', 'B9': '1', 'D1': '0'}
>>>Now I want to create a dict which would have both the keys and values to be of the corresponding values of dict2.
>>>Something like this:
>>>Eg. The first key in dict1 i.e. B8 as 0 (0 is the value of B8 in dict2) mapped as set(['0','0','0',...]).
>>>Can anyone help me out with this.  Anush
new_dict = {} for akey, aset in dict1.items(): new_dict[akey] = sum(int(dict2[k]) for k in aset)
James
So there is no way I can represent all the duplicates right.
So is there any solution where I could take the values of dictionary
and represent them separately?

Anush
Just leave off the sum and turn the generator into a list comprehension:
new_dict = {}
for akey, aset in dict1.items():
new_dict[akey] = [dict2[k] for k in aset]
James
>
Working from your original dict1:
dout = [[dict2[i], [dict2[k] for k in setvalue]]
for i,setvalue in dict1.iteritems()]
 Paddy
I dont think this works. This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics
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I've got a dictionary, A, that is arbitarily large and may contains
ints, None and more...

by: JamesB 
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I have a config screen in my app that updates a dictionary<key,value>.
I want to store a copy of this before going into the config screen so if the
user wants to cancel all their changes I can...

by: sachin2 
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I am using 3 types of dictionaries.
1) Dictionary<string, string > d = new Dictionary<string, string>();
2) Dictionary<string, List<string>> d = new Dictionary<string, List<string>>();
3)...

by: Charles Arthur 
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How do i turn on java script on a villaon, callus and itel keypad mobile phone

by: ryjfgjl 
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If we have dozens or hundreds of excel to import into the database, if we use the excel import function provided by database editors such as navicat, it will be extremely tedious and timeconsuming...

by: emmanuelkatto 
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Hi All, I am Emmanuel katto from Uganda. I want to ask what challenges you've faced while migrating a website to cloud.
Please let me know.
Thanks!
Emmanuel

by: BarryA 
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What are the essential steps and strategies outlined in the Data Structures and Algorithms (DSA) roadmap for aspiring data scientists? How can individuals effectively utilize this roadmap to progress...

by: nemocccc 
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hello, everyone, I want to develop a software for my android phone for daily needs, any suggestions?

by: Sonnysonu 
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This is the data of csv file
1 2 3
1 2 3
1 2 3
1 2 3
2 3
2 3
3
the lengths should be different i have to store the data by columnwise with in the specific length.
suppose the i have to...

by: Hystou 
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Most computers default to English, but sometimes we require a different language, especially when relocating. Forgot to request a specific language before your computer shipped? No problem! You can...

by: Oralloy 
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Hello folks,
I am unable to find appropriate documentation on the type promotion of bitfields when using the generalised comparison operator "<=>".
The problem is that using the GNU compilers,...

by: Hystou 
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Overview:
Windows 11 and 10 have less user interface control over operating system update behaviour than previous versions of Windows. In Windows 11 and 10, there is no way to turn off the Windows...
 