how to print out each single char from a string in HEX format?

[mike]

guys,

I've researched python pretty much but still have no idea how to print
out each single character from a string in HEX format? Hope someone
can give me some hints. Thanks a lot.

e.g. ###here is a string

a='01234'

###how to print out it out in this way

0x31 0x31 0x32 0x33 0x34

[Gabriel Genellina]

En Mon, 04 Jun 2007 20:03:39 -0300, mike <ne*********@gmail.comescribió:

I've researched python pretty much but still have no idea how to print
out each single character from a string in HEX format? Hope someone
can give me some hints. Thanks a lot.

e.g. ###here is a string

a='01234'

###how to print out it out in this way

0x31 0x31 0x32 0x33 0x34

pya='01234'
pyfor c in a:
.... print "%#x" % ord(c),
....
0x30 0x31 0x32 0x33 0x34
py>

See <http://docs.python.org/lib/built-in-funcs.html#l2h-55for the ord()
function and <http://docs.python.org/lib/typesseq-strings.htmlfor the
"%#x" format

--
Gabriel Genellina

[mike]

Great! It works.

Thanks a lot.

[Troels Thomsen]

Great! It works.

There is a builtin function called hex() that does the same, but also shares
the same problem as the solution above:

>>hex(10)

'0xa'

>>>

This is probably not "nice" in your printouts, it doesn't allign.
with the printf inspired solution you can set the precision like this:

>>a = "12\n34"
for c in a:

.... print "%#04x" % ord(c),
....
0x31 0x32 0x0a 0x33 0x34

>>>

regards troels

[Grant Edwards]

On 2007-06-05, Troels Thomsen <nejwrote:

with the printf inspired solution you can set the precision like this:

>>>a = "12\n34"
for c in a:

... print "%#04x" % ord(c),
...
0x31 0x32 0x0a 0x33 0x34

And if you just want to do the conversion w/o printing:

>>a = "12\n34"

>>' '.join(('%#04x' % ord(c) for c in a))

'0x31 0x32 0x0a 0x33 0x34'

>>' '.join(('%02x' % ord(c) for c in a))

'31 32 0a 33 34'

--
Grant Edwards grante Yow! Vote for ME -- I'm
at well-tapered, half-cocked,
visi.com ill-conceived and
TAX-DEFERRED!