By using this site, you agree to our updated Privacy Policy and our Terms of Use. Manage your Cookies Settings.
438,427 Members | 1,356 Online
Bytes IT Community
+ Ask a Question
Need help? Post your question and get tips & solutions from a community of 438,427 IT Pros & Developers. It's quick & easy.

[B,IX] = sort(A,...) - Order for sort()-function

P: n/a
Dear community,

I want to use the sort function to sort a (nested) list. General information can be found below.

I want to solve the following problem. Given a list I do not only want to retrieve the sorted list but also the position of the original elements (IX below). The example is taken from Matlab syntax:

'[B,IX] = sort(A,...) also returns an array of indices IX, where size(IX) == size(A). If A is a vector, B = A(IX). If A is an m-by-n matrix, then each column of IX is a permutation vector of the corresponding column of A, such that
for j = 1:n
B(:,j) = A(IX(:,j),j);

A = [ 3 7 5
0 4 2 ];

# in Python: A = [[3,7,5],[0,4,2]]

[B,IX] = sort(A,2)

# sort by rows

B =
3 5 7
0 2 4

IX =
1 3 2
1 3 2

# first line: 3 was formerly in the first position, 5 formerly in position 3, 7 formerly in position 2
# second line: similiarly


Psssst! Schon vom neuen GMX MultiMessenger gehört?
Der kanns mit allen:
May 29 '07 #1
Share this question for a faster answer!
Share on Google+

This discussion thread is closed

Replies have been disabled for this discussion.