how to use private method in a class

[wang frank]

Hi,

I am trying to write a python class with a new data type such as:
class Cc14:
def __init__(self, realpart, imagpart):
self.r=realart
self.i=imagpart

def __saturator(x):
return x+1
def out(self,x):
return Cc14(__saturator(x.r), __saturator(x,i))

When I use the method out such as:
z.out

Python complains:

global name '_Cc14_saturator' is not defined.

Is the way put two underscore in front of the definitio making the method
becomes private?

Why in the same clase, I could not use the __saturator method?

Thanks

Frank

>From: "wang frank" <fw*@hotmail.co.jp>
To: py*********@python.org
Subject: A newbie question
Date: Mon, 21 May 2007 23:04:06 +0000

Hi,

I am trying to write a python class with a new data type such as:
class Cc14:
def __init__(self, realpart, imagpart):
self.r=realart
self.i=imagpart

def __add__(self,x):
return self.r+x,r, self.i+x.i

If I have
x=Cc14(4,5)
y=Cc14(4,5)
z=x+y

z will be a tuple instead of Cc14. How can I return a Cc14 class?

Thanks
Frank

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[Basilisk96]

On May 21, 9:49 pm, "wang frank" <[e-mail]:

Hi,

I am trying to write a python class with a new data type such as:
class Cc14:
def __init__(self, realpart, imagpart):
self.r=realart
self.i=imagpart

def __saturator(x):
return x+1
def out(self,x):
return Cc14(__saturator(x.r), __saturator(x,i))

When I use the method out such as:
z.out

Python complains:

global name '_Cc14_saturator' is not defined.

Is the way put two underscore in front of the definitio making the method
becomes private?

Why in the same clase, I could not use the __saturator method?

Thanks

Frank

It seems you have several issues here:

(1) To avoid syntax errors,
self.r=realart
should be:
self.r=realpart

(2) Your __saturator method definition needs the reference to self:
def __saturator(self, x):

(3) And lastly, the body of the out() method needs two corrections:
return Cc14(self.__saturator(x.r), self.__saturator(x.i))

Is it really necessary to "privatize" the saturator method? In Python,
all class methods are public and visible by default. A method name
__methodname in a class "foo" turns into "_foo__methodname" in an
instance of the class. This is known as name mangling. It is simply a
convention supported by Python when a class attribute name begins with
two underscores. It prevents a programmer from calling something like
C.__saturator(arg), but still allows calling C._Cc14__saturator(arg).

IMHO, you could just leave the saturator definition as "def
saturator(self, x):"

Anyway, in your case the 3 fixes above will allow you now to do this:

>>>C = Cc14(2,3)
result = C.out(C)
result.r, result.i

(3, 4)

Which is beginning to look like your design intent..

Cheers,
-Basilisk96