How to get a date after a month in python

[parthpatel]

Suppose i have a date as (2007 / 04 / 25)


now i need a date exactly after a month i.e. (2007 / 05 / 25)

Is there any function which can help it out

[bvdet]

Suppose i have a date as (2007 / 04 / 25)


now i need a date exactly after a month i.e. (2007 / 05 / 25)

Is there any function which can help it out

>>> import datetime
>>> dt = '2007 / 04 / 25'
>>> d = datetime.date(*[int(i) for i in dt.split(' / ')])
>>> d1 = d.replace(month=d.month+1)
>>> dt = d1.strftime('%Y / %m / %d')
>>> dt
'2007 / 05 / 25'
>>> 

[dshimer]

(*[int(i) for i in dt.split(' / ')]) 

I have see you use this syntax before, could you (or anyone who gets it explain it once, or tell me where I can get a decent explanation.

I am refering to the idea of putting the for loop and assigning the return values all in a single statement.

I see it work, but just don't get the mechanics of it.

[bvdet]

(*[int(i) for i in dt.split(' / ')]) 

I have see you use this syntax before, could you (or anyone who gets it explain it once, or tell me where I can get a decent explanation.

I am refering to the idea of putting the for loop and assigning the return values all in a single statement.

I see it work, but just don't get the mechanics of it.

It wasn't easy for me to understand either. There are two components to explain. First is the list comprehension of the form '[expression for item in list if condition]'.

>>> [i for i in range(10)]
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
>>> [(i+12)/4.5 for i in range(10) if i == 6]
[4.0]
>>> 

The '*' preceding the list comprehension expands the list as though the list elements were passed to the function as arguments. I think of it as the '*' removes the list brackets. In the example, the equivalent code is:

dt = '2007 / 05 / 25'
dtList = dt.split(' / ')
d = datetime.date(int(dtList[0]), int(dtList[1]), int(dtList[2]))
 
print d
print repr(d)
'''2007-05-25
datetime.date(2007, 5, 25)
>>>
'''

HTH :)

[dshimer]

WOW! Thanks, that is too cool.