How to open a txt file from the same folder as my module (w/outchanging the working dir)

[Sergio Correia]

I have a program in 'C:\Python25\Lib\site-packages\spam\spam.py'

Importing and everything works fine:

>>from spam import spam

But the program calls a file located on the same folder (that is:
C:\Python25\Lib\site-packages\spam\).

How do i do that?

>>spam.eggs()

Traceback (most recent call last):
File "<pyshell#21>", line 1, in <module>
datita = spam.eggs()
File "C:\Python25\lib\site-packages\spam\spam.py", line 149, in JustDoIt
config = open("configuration.txt", "rb").read().split('\r\n')
IOError: [Errno 2] No such file or directory: 'configuration.txt'

My last resort is to hard code the path for that file, but it's ugly,
and I want to know if I'm missing something. Am I?

Thanks a lot,
Sergio

[Larry Bates]

Sergio Correia wrote:

I have a program in 'C:\Python25\Lib\site-packages\spam\spam.py'

Importing and everything works fine:

>>>from spam import spam

But the program calls a file located on the same folder (that is:
C:\Python25\Lib\site-packages\spam\).

How do i do that?

>>>spam.eggs()

Traceback (most recent call last):
File "<pyshell#21>", line 1, in <module>
datita = spam.eggs()
File "C:\Python25\lib\site-packages\spam\spam.py", line 149, in JustDoIt
config = open("configuration.txt", "rb").read().split('\r\n')
IOError: [Errno 2] No such file or directory: 'configuration.txt'

My last resort is to hard code the path for that file, but it's ugly,
and I want to know if I'm missing something. Am I?

Thanks a lot,
Sergio

The problem is that C:\Python25\Lib\site-packages\spam is not
the current working directory when you run the program. If it were,
and if configuration.txt is in that directory it WILL find it. If
you are running this from a shortcut make the working directory
C:\Python25\Lib\site-packages\spam

-Larry

[Gabriel Genellina]

En Wed, 04 Apr 2007 20:14:37 -0300, Larry Bates <la*********@websafe.com>
escribió:

Sergio Correia wrote:

>I have a program in 'C:\Python25\Lib\site-packages\spam\spam.py'

Importing and everything works fine:

>>>>from spam import spam

But the program calls a file located on the same folder (that is:
C:\Python25\Lib\site-packages\spam\).

How do i do that?

The problem is that C:\Python25\Lib\site-packages\spam is not
the current working directory when you run the program. If it were,
and if configuration.txt is in that directory it WILL find it. If
you are running this from a shortcut make the working directory
C:\Python25\Lib\site-packages\spam

If changing the working directory is not possible/convenient, use the
module __file__ attribute (spam.__file__) to obtain the directory where
spam.py resides.

--
Gabriel Genellina

[Sergio Correia]

Larry, Gabriel

Thanks for the replies. Both ways work great.

Sergio

On 4/4/07, Gabriel Genellina <ga*******@yahoo.com.arwrote:

En Wed, 04 Apr 2007 20:14:37 -0300, Larry Bates <la*********@websafe.com>
escribió:

Sergio Correia wrote:

I have a program in 'C:\Python25\Lib\site-packages\spam\spam.py'

Importing and everything works fine:
from spam import spam

But the program calls a file located on the same folder (that is:
C:\Python25\Lib\site-packages\spam\).

How do i do that?

The problem is that C:\Python25\Lib\site-packages\spam is not
the current working directory when you run the program. If it were,
and if configuration.txt is in that directory it WILL find it. If
you are running this from a shortcut make the working directory
C:\Python25\Lib\site-packages\spam

If changing the working directory is not possible/convenient, use the
module __file__ attribute (spam.__file__) to obtain the directory where
spam.py resides.

--
Gabriel Genellina

--
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