HELP plz [to determine leap year]

[xGx]

Hi please could someone help. i have created this programming so you can work out if there is a LEAP YEAR. But i need it to handle centuries. heres the code

def isLeapYear (year):
    result = year % 4
    if result > 0:
        print "It is NOT a leap year"
    else:
        print "It IS a leap year"
 
        Result = (year * 100) % 4
        if result >0:
            print "It is NOT a leap year"
 
isLeapYear(400)
isLeapYear(800)
isLeapYear(1600)
isLeapYear(1601)
isLeapYear(2004)
isLeapYear(2012)
isLeapYear(3010)
isLeapYear(3330)
 
 

Please can someone help me out sort it out. THANX

[ilikepython]

We can help but your code would be easier to understand if you use code tags around your code. See the posting guidelines for help with that.
Repost your code and someone will help you

[bartonc]

Hi please could someone help. i have created this programming so you can work out if there is a LEAP YEAR. But i need it to handle centuries. heres the code

def isLeapYear (year):
    result = year % 4
    if result > 0:
        print "It is NOT a leap year"
    else:
        print "It IS a leap year"
 
        Result = (year * 100) % 4
        if result >0:
            print "It is NOT a leap year"
 
isLeapYear(400)
isLeapYear(800)
isLeapYear(1600)
isLeapYear(1601)
isLeapYear(2004)
isLeapYear(2012)
isLeapYear(3010)
isLeapYear(3330)
 
 

Please can someone help me out sort it out. THANX

Capital 'R' is messing you up.

        Result = (year * 100) % 4
 

[hidrkannan]

Capital 'R' is messing you up.

        Result = (year * 100) % 4
 

Last2Digits = year % 100
if (Last2Digits == 0):
    flag = year % 400
else:
    flag = year % 4
 
if (flag == 0):
    print " is a Leap year"
else:
    print " is not a Leap year"