Converting a list to a dictionary

[Samuel]

Hi,

is there a short version for this?

res_dict = {}
for resource in res_list:
res_dict[resource.get_id()] = resource

This does not work:

res_dict = dict([r.get_id(), r for r in res_list])

-Samuel

[Bruno Desthuilliers]

Samuel a écrit :

Hi,

is there a short version for this?

res_dict = {}
for resource in res_list:
res_dict[resource.get_id()] = resource

This does not work:

res_dict = dict([r.get_id(), r for r in res_list])

res_dict = dict((r.get_id(), r) for r in res_list)

or if you have to be compatible with older python versions:

res_dict = dict([(r.get_id(), r) for r in res_list])

HTH

[Leif K-Brooks]

Samuel wrote:

This does not work:

res_dict = dict([r.get_id(), r for r in res_list])

This does:

res_dict = dict([(r.get_id(), r) for r in res_list])

[Samuel]

On Mar 14, 9:52 pm, Bruno Desthuilliers
<[e-mail]:

res_dict = dict((r.get_id(), r) for r in res_list)

or if you have to be compatible with older python versions:

res_dict = dict([(r.get_id(), r) for r in res_list])

Yep, that works. Strange, I was sure I had tested the latter, but I
must have been doing something wrong.

Thanks for your help!

-Samuel

[Drew]

On Mar 14, 4:52 pm, Bruno Desthuilliers
<[e-mail]:

res_dict = dict((r.get_id(), r) for r in res_list)

I'm using Python2.5 and it seems that this only gives me a hash with
the first id and first record. Am I doing something wrong?

>>class Person():

.... def __init__(self):
.... self.id = 5
....

>>mylist = []
for i in range(100):

.... mylist.append(Person())
....

>>mydict = dict((r.id,r) for r in mylist)
mydict

{5: <__main__.Person instance at 0x00A99EE0>}

>>>

[Samuel]

On Mar 14, 9:32 pm, "Drew" <[e-mail]:

I'm using Python2.5 and it seems that this only gives me a hash with
the first id and first record. Am I doing something wrong?

Try this instead:

>>class Person():

.... def __init__(self):
.... self.id = 5
....

>>mylist = []
for i in range(100):

.... p = Person()
.... p.id = i
.... mylist.append(p)
....

>>mydict = dict((r.id,r) for r in mylist)
mydict

What this does is it maps the id to the object. In your case, you only
have one id.

-Samuel

[Drew]

On Mar 14, 4:43 pm, "Samuel" <[e-mail]:

What this does is it maps the id to the object. In your case, you only
have one id.

-Samuel

This is interesting behavior, but may not be what the original poster
intended. If I understand correctly, this means that if more than one
object shares the same id, only one copy will be created in the dict.
Is this correct?

[Samuel]

On Mar 14, 9:48 pm, "Drew" <[e-mail]:

This is interesting behavior, but may not be what the original poster
intended.

I am the original poster :).

If I understand correctly, this means that if more than one
object shares the same id, only one copy will be created in the dict.
Is this correct?

Yes. Dictionaries are just hashes; you can't have the same key twice.

Bye,
-Sam

[Steve Holden]

Drew wrote:

On Mar 14, 4:52 pm, Bruno Desthuilliers
<[e-mail]:

>res_dict = dict((r.get_id(), r) for r in res_list)

I'm using Python2.5 and it seems that this only gives me a hash with
the first id and first record. Am I doing something wrong?

>>>class Person():

... def __init__(self):
... self.id = 5
...

>>>mylist = []
for i in range(100):

... mylist.append(Person())
...

>>>mydict = dict((r.id,r) for r in mylist)
mydict

{5: <__main__.Person instance at 0x00A99EE0>}

Well, you aren't actually using the object's id() value as the dict key,
but the value of its id attribute. Since all the instances you create
have the same value for that attribute each change to the dict (except
the first) overwrites the immediately preceding change - you can't have
100 values in a dict all with the same key!

Try:

>>mydict = dict((id(r), r) for r in mylist)

and you'll find you then get a dict with 100 elements.

regards
Steve
--
Steve Holden [phone] [phone]
Holden Web LLC/Ltd http://www.holdenweb.com
Skype: holdenweb http://del.icio.us/steve.holden
Blog of Note: http://holdenweb.blogspot.com
See you at PyCon? http://us.pycon.org/TX2007

[Drew]

On Mar 14, 4:52 pm, "Samuel" <[e-mail]:

On Mar 14, 9:48 pm, "Drew" <[e-mail]:

This is interesting behavior, but may not be what the original poster
intended.

I am the original poster :).

If I understand correctly, this means that if more than one
object shares the same id, only one copy will be created in the dict.
Is this correct?

Yes. Dictionaries are just hashes; you can't have the same key twice.

Bye,
-Sam

Doh! *Hangs head in shame and walks away slowly...* Thanks for you
gracious response :)