Matching Strings

[rshepard]

I'm not sure how to change a string so that it matches another one.

My application (using wxPython and SQLite3 via pysqlite2) needs to compare
a string selected from the database into a list of tuples with another
string selected in a display widget.

An extract of the relevant code is:

selName = self.polTree.GetItemText(selID)
...
for item in self.appData.polNat:
print 'Item: ', item, '\n', 'selName: ', selName, '\n'
if item == selName:
print '***** ', self.appData.polNat[1]

The last comparison and print statement never work because the strings are
presented this way:

Item: (u'ground water',)
selName: ground water

What do I need to do to 'Item' to strip the parentheses, unicode symbol,
single quotes, and comma? Do I want 'raw' output? If so, how do I specify
that in the line 'if item == selName:'?

TIA,

Rich

[James Stroud]

rs******@nospam.appl-ecosys.com wrote:

I'm not sure how to change a string so that it matches another one.

My application (using wxPython and SQLite3 via pysqlite2) needs to compare
a string selected from the database into a list of tuples with another
string selected in a display widget.

An extract of the relevant code is:

selName = self.polTree.GetItemText(selID)
...
for item in self.appData.polNat:
print 'Item: ', item, '\n', 'selName: ', selName, '\n'
if item == selName:
print '***** ', self.appData.polNat[1]

The last comparison and print statement never work because the strings are
presented this way:

Item: (u'ground water',)
selName: ground water

What do I need to do to 'Item' to strip the parentheses, unicode symbol,
single quotes, and comma? Do I want 'raw' output? If so, how do I specify
that in the line 'if item == selName:'?

TIA,

Rich

Assuming item is "(u'ground water',)"

import re
item = re.compile(r"\(u'([^']*)',\)").search(item).group(1)

James

[Paul McGuire]

On Feb 9, 6:03 pm, [e-mail] wrote:

I'm not sure how to change a string so that it matches another one.

My application (using wxPython and SQLite3 via pysqlite2) needs to compare
a string selected from the database into a list of tuples with another
string selected in a display widget.

An extract of the relevant code is:

selName = self.polTree.GetItemText(selID)
...
for item in self.appData.polNat:
print 'Item: ', item, '\n', 'selName: ', selName, '\n'
if item == selName:
print '***** ', self.appData.polNat[1]

The last comparison and print statement never work because the strings are
presented this way:

Item: (u'ground water',)
selName: ground water

What do I need to do to 'Item' to strip the parentheses, unicode symbol,
single quotes, and comma? Do I want 'raw' output? If so, how do I specify
that in the line 'if item == selName:'?

TIA,

Rich

I suspect that the variable item is *not* a string, but a tuple whose
zero'th element is a unicode string with the value u'ground water'.
Try comparing item[0] with selname.

>From my command prompt:

>>u'a' == 'a'

True

-- Paul

[Gabriel Genellina]

En Fri, 09 Feb 2007 21:03:32 -0300, <rs******@nospam.appl-ecosys.com>
escribió:

I'm not sure how to change a string so that it matches another one.

My application (using wxPython and SQLite3 via pysqlite2) needs to
compare
a string selected from the database into a list of tuples with another
string selected in a display widget.

An extract of the relevant code is:

selName = self.polTree.GetItemText(selID)
...
for item in self.appData.polNat:
print 'Item: ', item, '\n', 'selName: ', selName, '\n'
if item == selName:
print '***** ', self.appData.polNat[1]

The last comparison and print statement never work because the strings
are
presented this way:

Item: (u'ground water',)
selName: ground water

Forget about re and slicing and blind guessing...
item appears to be a tuple; in these cases repr is your friend. See what
happens with:
print repr(item), type(item)

If it is in fact a tuple, you should ask *why* is it a tuple (maybe could
have many items?). And if it's just an artifact and actually it always
will be a single:

assert len(item)==1
item = item[0]
if item...

--
Gabriel Genellina

[rshepard-at-appl-ecosys.com]

On 2007-02-10, James Stroud <js*****@mbi.ucla.eduwrote:

Assuming item is "(u'ground water',)"

import re
item = re.compile(r"\(u'([^']*)',\)").search(item).group(1)

James,

I solved the problem when some experimentation reminded me that 'item' is
a list index and not a string variable. by changing the line to,

if item[0] == selName:

I get the matchs correctly.

Now I need to extract the proper matching strings from the list of tuples,
and I'm working on that.

Many thanks,

Rich

[John Machin]

On Feb 10, 11:03 am, [e-mail] wrote:

I'm not sure how to change a string so that it matches another one.

My application (using wxPython and SQLite3 via pysqlite2) needs to compare
a string selected from the database into a list of tuples with another
string selected in a display widget.

Tuple? Doesn't that give you a clue?

>
An extract of the relevant code is:

selName = self.polTree.GetItemText(selID)
...
for item in self.appData.polNat:
print 'Item: ', item, '\n', 'selName: ', selName, '\n'
if item == selName:
print '***** ', self.appData.polNat[1]

The last comparison and print statement never work because the strings are
presented this way:

What you mean is: The way you have presented the strings is confusing
you, and consequently you have written a comparison that will not
work :-)

>
Item: (u'ground water',)

Hmmmm. That comma in there is interesting. I wonder where the
parentheses came from. What did the man mutter about a list of tuples?

selName: ground water

What do I need to do to 'Item' to strip the parentheses, unicode symbol,
single quotes, and comma?

Nothing. They're not there. It's all in your mind.

Do I want 'raw' output?

What is "raw output"?

If so, how do I specify
that in the line 'if item == selName:'?

That's a comparison, not output.

Step 1: Find out what you've *really* got there:

Instead of
print 'Item: ', item, '\n', 'selName: ', selName, '\n'
do this:
print 'item', repr(item), type(item)
print 'selName', repr(selName), type(selName)

Step 2:
Act accordingly.

Uncle John's Crystal Balls (TM) predict that you probably need this:
if item[0] == selName:

HTH,
John

[John Machin]

On Feb 10, 12:01 pm, rshepard-at-appl-ecosys.com wrote:

On 2007-02-10, James Stroud <[e-mail]:

Assuming item is "(u'ground water',)"

import re
item = re.compile(r"\(u'([^']*)',\)").search(item).group(1)

James,

I solved the problem when some experimentation reminded me that 'item' is
a list index

AArrgghh it's not a list index, it's a ferschlugginer tuple containing
1 element.

[Steven D'Aprano]

On Fri, 09 Feb 2007 16:17:31 -0800, James Stroud wrote:

Assuming item is "(u'ground water',)"

import re
item = re.compile(r"\(u'([^']*)',\)").search(item).group(1)

Using a regex is a lot of overhead for a very simple operation.

If item is the string "(u'ground water',)"

then item[3:-3] will give "ground water".

>>import re, timeit
item = "(u'ground water',)"

>>timeit.Timer('item[3:-3]', 'from __main__ import item').repeat()

[0.56174778938293457, 0.53341794013977051, 0.53485989570617676]

>>timeit.Timer( \

.... '''re.compile(r"\(u'([^']*)',\)").search(item).group(1)''', \
.... 'from __main__ import item; import re').repeat()
[9.2723720073699951, 9.2299859523773193, 9.2523660659790039]
However, as many others have pointed out, the Original Poster's problem
isn't that item has leading brackets around the substring he wants, but
that it is a tuple.

--
Steven.