Trailing L on Longs

[TMS]

by using __repr__(), is there a way to omit the trailing L when representing a (num/den)?

[bvdet]

by using __repr__(), is there a way to omit the trailing L when representing a (num/den)?

>>> repr(5788769978008/2)
'2894384989004L'
>>> repr(str(5788769978008/2))
"'2894384989004'"
>>> repr(float(5788769978008/2))
'2894384989004.0'
>>> repr(float(5788769978008/2))[:-2]
'2894384989004'
>>> 

HTH,
BV

[bartonc]

by using __repr__(), is there a way to omit the trailing L when representing a (num/den)?

How about just

>>> str(5788769978008/2)
'2894384989004'
>>>

[TMS]

ok, make it a string. I see. Thank you

[bartonc]

ok, make it a string. I see. Thank you

You are welcome.

[cybervegan]

Another way is to use python's c-like sting formatting to do the job:

print "This is a long: %i" % 12345123451234512345L
 
print "Here are a few values: a string %s; a float %7.3f; an integer %-5i" % ("doobery",1234.567,0123)

It's generally more efficient (and readable and maintainable) to use string formats for complex output, but if you just want to print a number, it can be cumbersome. Your call.

hth,
-cybervegan

[bartonc]

Another way is to use python's c-like sting formatting to do the job:

print "This is a long: %i" % 12345123451234512345L
 
print "Here are a few values: a string %s; a float %7.3f; an integer %-5i" % ("doobery",1234.567,0123)

It's generally more efficient (and readable and maintainable) to use string formats for complex output, but if you just want to print a number, it can be cumbersome. Your call.

hth,
-cybervegan

Great post, cybervegan. Thanks.