Calling J from Python

[Gosi]

It is quite easy to call J from Python

http://groups.google.com/group/J-Pro...84b75667f5f64e

[Nick Craig-Wood]

George Sakkis <ge***********@gmail.comwrote:

On Feb 9, 9:20 pm, [e-mail] wrote:

This is a bit simpler, but probably there are simpler solutions using
modular arithmetic:

l = [1]
for _ in range(15):
print ''.join(" *"[x] for x in l)
l = [1] + [l[i+1]^l[i] for i in range(len(l)-1)] + [1]

Bye,
bearophile

Here's another one, adapted from the example (in Java) in Wikipedia's
entry (http://en.wikipedia.org/wiki/Sierpinski_triangle):

N=15
for x in xrange(N,0,-1):
print ''.join('* '[x&y!=0] for y in xrange(N+1-x))

This is my solution after a few minutes thought.

It uses a different algorithm for generating the triangle. If python
could output binary numbers it would be more elegant...

>>n = 1
for i in range(16):

.... print ("%X" % n).replace('0', ' ').replace('1', '*')
.... n = n ^ (n << 4)
....
*
**
* *
****
* *
** **
* * * *
********
* *
** **
* * * *
**** ****
* * * *
** ** ** **
* * * * * * * *
****************
--
Nick Craig-Wood <ni**@craig-wood.com-- http://www.craig-wood.com/nick