Confusion over calling a nested function inside a parent function

[Pyenos]

class WORK:
def getwork(self):
def choosetable(self):pass
choosetable() #TypeError: choosetable() takes exactly 1
#argument (0 given)
 

Calling choosetable() at the above location gives me the error
described above.

[MacDonald]

Pyenos wrote:

class WORK:
    def getwork(self):
        def choosetable(self):pass
        choosetable() #TypeError: choosetable() takes exactly 1
                      #argument (0 given)
 

Calling choosetable() at the above location gives me the error
described above.

Although choosetable is a memeber of an instance method, it is not one
itself. It should not have self as it's first formal parameter.

[Duncan Booth]

Pyenos <py****@pyenos.orgwrote:

class WORK:
    def getwork(self):
        def choosetable(self):pass
        choosetable() #TypeError: choosetable() takes exactly 1
                      #argument (0 given)
 

Calling choosetable() at the above location gives me the error
described above.

A function defined inside a method is just a function, it's only when a
function is retrieved from the class dictionary (whether it was defined
there or assigned to the class later) that it becomes a method.

Just leave the self parameter off the choosetable function: you can still
access self from the outer scope of getwork.

[Pyenos]

"MacDonald" <cr*******@gmail.comwrites:

Pyenos wrote:

 class WORK:
     def getwork(self):
         def choosetable(self):pass
         choosetable() #TypeError: choosetable() takes exactly 1
                       #argument (0 given)
 

Calling choosetable() at the above location gives me the error
described above.

Although choosetable is a memeber of an instance method, it is not one
itself. It should not have self as it's first formal parameter.

class WORK:
def getwork(self):
def choosetable():pass
choosetable()
 

like this? thank you! ;-)

[Bruno Desthuilliers]

MacDonald a écrit :

Pyenos wrote:

>>

class WORK:
   def getwork(self):
       def choosetable(self):pass
       choosetable() #TypeError: choosetable() takes exactly 1
                     #argument (0 given)

Calling choosetable() at the above location gives me the error
described above.

Although choosetable is a memeber of an instance method,

s/is a member of/is defined in/

[Bruno Desthuilliers]

Pyenos a écrit :

[code]

You already got the answer - just a pair of stylistic advices:

class WORK:

1/ By convention, ALL_UPPER names denote (pseudo) symbolic constants.
The convention for class names is CamelCase.

2/ better to use new-style classes.

=>
class Work(object):
...