list1.append(list2) returns None

[Pyenos]

def enlargetable(table,col):
return table.append(col)

def removecolfromtable(table,col):
return table.remove(col)

print enlargetable([[1],[2],[3]],[4]) # returns None

Why does it return None instead of [[1],[2],[3],[4]] which I expected?

[Todd Neal]

Pyenos wrote:

def enlargetable(table,col):
return table.append(col)

def removecolfromtable(table,col):
return table.remove(col)

print enlargetable([[1],[2],[3]],[4]) # returns None

Why does it return None instead of [[1],[2],[3],[4]] which I expected?

append modifies the list and then returns None:

>>print a

[1, 2, 3]

>>print a.append(4)

None

>>print a

[1, 2, 3, 4]
The reasoning given at
http://www.python.org/doc/faq/genera...he-sorted-list
is so you wont do something like this:

a = [1,2,3]
b = a.append(4)

and assume that a is still [1,2,3]
More discussion on this topic is available at
http://groups.google.com/group/comp....b2e67550123b92

Todd

[Edward Kozlowski]

Pyenos wrote:

def enlargetable(table,col):
return table.append(col)

def removecolfromtable(table,col):
return table.remove(col)

print enlargetable([[1],[2],[3]],[4]) # returns None

Why does it return None instead of [[1],[2],[3],[4]] which I expected?

return the table. Ex:

def enlargetable(table, col):
table.append(col)
return table

[Gabriel Genellina]

def enlargetable(table,col):

return table.append(col)

Google for "python pitfalls"

--
Gabriel Genellina

[Ben Finney]

Pyenos <py****@pyenos.orgwrites:

def enlargetable(table,col):
return table.append(col)

def removecolfromtable(table,col):
return table.remove(col)

print enlargetable([[1],[2],[3]],[4]) # returns None

Why does it return None instead of [[1],[2],[3],[4]] which I expected?

The answer is both "because that's what it's documented to do":

s.append(x) same as s[len(s):len(s)] = [x]
<URL:http://docs.python.org/lib/typesseq-mutable.html>

and "because you asked it to *do* something, not *get* something":

<URL:http://www.python.org/doc/faq/general.html#why-doesn-t-list-sort-return-the-sorted-list>

--
\ "There was a point to this story, but it has temporarily |
`\ escaped the chronicler's mind." -- Douglas Adams |
_o__) |
Ben Finney

[Steven D'Aprano]

On Thu, 21 Dec 2006 16:29:01 +1100, Ben Finney wrote:

Pyenos <py****@pyenos.orgwrites:

>def enlargetable(table,col):
return table.append(col)

def removecolfromtable(table,col):
return table.remove(col)

print enlargetable([[1],[2],[3]],[4]) # returns None

Why does it return None instead of [[1],[2],[3],[4]] which I expected?

The answer is both "because that's what it's documented to do":

Documentation is a funny thing...

help([].append)

Help on built-in function append:

append(...)
L.append(object) -- append object to end

Sometimes it is hard to tell when you've read enough documentation.
However, as a general rule, "None whatsoever" is rarely enough.

--
Steven

[Pyenos]

i rewrote the code following the advices from subdir of the parent thread:

# well, table is composed of a list of columns.
# so let's stick them together
def enlargetable(table,col):
table.append(col) # the code won't return sorted lists :-o
return_the_fucking_table_bitch=table # assign it to a new variable to return it
return return_the_fucking_table_bitch # :-|
def removecolfromtable(table,col):
return table.remove(col)

print enlargetable([[1],[2],[3]],[4])

# and this code works.

[Georg Brandl]

Pyenos schrieb:

i rewrote the code following the advices from subdir of the parent thread:

# well, table is composed of a list of columns.
# so let's stick them together
def enlargetable(table,col):
table.append(col) # the code won't return sorted lists :-o

Why should it sort the list?

return_the_fucking_table_bitch=table # assign it to a new variable to return it
return return_the_fucking_table_bitch # :-|

That isn't necessary. A simple "return table" is fine.

>
def removecolfromtable(table,col):
return table.remove(col)

table.remove() also returns None.

print enlargetable([[1],[2],[3]],[4])

# and this code works.

Georg

[Matimus]

Pyenos wrote:

def enlargetable(table,col):
table.append(col) # the code won't return sorted lists :-o
return_the_fucking_table_bitch=table # assign it to a new variable to return it
return return_the_fucking_table_bitch # :-|

Maybe you were just trying to be funny, but assiging the table to
another variable before returning is not only unnecessary, it
accomplishes nothing. The following will do exactly the same thing as
the above:

def enlargetable(table,col):
table.append(col)
return table
 

[Gabriel Genellina]

At Thursday 21/12/2006 14:50, Matimus wrote:

>The following will do exactly the same thing as
the above:

def enlargetable(table,col):
    table.append(col)
    return table

Which, by the way, was one of the first answers he got, by Edward Kozlowski.
--
Gabriel Genellina
Softlab SRL


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