get script path

[hg]

Hi,

must I parse argv[0] to get it, or is there an easier way (that works under
Windows and *nix)?

Ex:

python /home/hg/test/test.py ==test.py #knows it is in /home/hg/test

Thanks,

hg

[hg]

hg wrote:

Hi,

must I parse argv[0] to get it, or is there an easier way (that works
under Windows and *nix)?

Ex:

python /home/hg/test/test.py ==test.py #knows it is in /home/hg/test

Thanks,

hg

got it: os.path.dirname(sys.argv [0])

[Rob Wolfe]

hg wrote:

Hi,

must I parse argv[0] to get it, or is there an easier way (that works under
Windows and *nix)?

Ex:

python /home/hg/test/test.py ==test.py #knows it is in /home/hg/test

IMHO it is easy enough:

>>dname, fname = os.path.split("/home/hg/test/test.py")
dname

'/home/hg/test'

--
HTH,
Rob

[hg]

Rob Wolfe wrote:

>
hg wrote:

>Hi,

must I parse argv[0] to get it, or is there an easier way (that works
under Windows and *nix)?

Ex:

python /home/hg/test/test.py ==test.py #knows it is in /home/hg/test

IMHO it is easy enough:

>>>dname, fname = os.path.split("/home/hg/test/test.py")
dname

'/home/hg/test'

--
HTH,
Rob

thanks