urllib.urlopen: Errno socket error

[kgrafals]

Hi,

I'm just trying to read from a webpage with urllib but I'm getting
IOErrors. This is my code:

import urllib
sock = urllib.urlopen("http://www.google.com/")

and this is the error:

Traceback (most recent call last):
File "<pyshell#5>", line 1, in <module>
sock = urllib.urlopen("http://www.google.com/")
File "C:\Python25\lib\urllib.py", line 82, in urlopen
return opener.open(url)
File "C:\Python25\lib\urllib.py", line 190, in open
return getattr(self, name)(url)
File "C:\Python25\lib\urllib.py", line 325, in open_http
h.endheaders()
File "C:\Python25\lib\httplib.py", line 856, in endheaders
self._send_output()
File "C:\Python25\lib\httplib.py", line 728, in _send_output
self.send(msg)
File "C:\Python25\lib\httplib.py", line 695, in send
self.connect()
File "C:\Python25\lib\httplib.py", line 679, in connect
raise socket.error, msg
IOError: [Errno socket error] (10060, 'Operation timed out')

I'm behind my company's firewall. Would that cause a problem? If it
does, How do I get around it?

[Salvatore]

Hello,

Try to increase the time out : socket.settimeout(n)
and catch the timeout error when it occurs

Regards

kg******@gmail.com a écrit :

Hi,

I'm just trying to read from a webpage with urllib but I'm getting
IOErrors. This is my code:

import urllib
sock = urllib.urlopen("http://www.google.com/")

and this is the error:

Traceback (most recent call last):
File "<pyshell#5>", line 1, in <module>
sock = urllib.urlopen("http://www.google.com/")
File "C:\Python25\lib\urllib.py", line 82, in urlopen
return opener.open(url)
File "C:\Python25\lib\urllib.py", line 190, in open
return getattr(self, name)(url)
File "C:\Python25\lib\urllib.py", line 325, in open_http
h.endheaders()
File "C:\Python25\lib\httplib.py", line 856, in endheaders
self._send_output()
File "C:\Python25\lib\httplib.py", line 728, in _send_output
self.send(msg)
File "C:\Python25\lib\httplib.py", line 695, in send
self.connect()
File "C:\Python25\lib\httplib.py", line 679, in connect
raise socket.error, msg
IOError: [Errno socket error] (10060, 'Operation timed out')

I'm behind my company's firewall. Would that cause a problem? If it
does, How do I get around it?

[kgrafals]

Hi Salvatore,

Even if I catch the exceptions in a loop it goes on forever.

- ken

[kgrafals]

Dennis,

I tried a ProxyHandler with the following code ...

proxy_support = urllib2.ProxyHandler({})
opener = urllib2.build_opener(proxy_support)
urllib2.install_opener(opener)

.... but it's giving me the same result.

Then I tried to tunnel using code from ...

http://aspn.activestate.com/ASPN/Coo.../Recipe/213238

.... but it too gave me an error ...

Traceback (most recent call last):
File "<pyshell#7>", line 1, in <module>
tunnel.run(tunnel_this)
File "C:/Python25/My Python/PyTunnel.py", line 124, in run
Threads.append( thread_it(tid=0,proxy=self.get_proxy(),\
File "C:/Python25/My Python/PyTunnel.py", line 81, in get_proxy
proxy.connect((self._phost,self._pport))
File "<string>", line 1, in connect
gaierror: (11001, 'getaddrinfo failed')

[frifri007]

kg******@gmail.com a écrit :

Hi,

I'm just trying to read from a webpage with urllib but I'm getting
IOErrors. This is my code:

import urllib
sock = urllib.urlopen("http://www.google.com/")

and this is the error:

Traceback (most recent call last):
File "<pyshell#5>", line 1, in <module>
sock = urllib.urlopen("http://www.google.com/")
File "C:\Python25\lib\urllib.py", line 82, in urlopen
return opener.open(url)
File "C:\Python25\lib\urllib.py", line 190, in open
return getattr(self, name)(url)
File "C:\Python25\lib\urllib.py", line 325, in open_http
h.endheaders()
File "C:\Python25\lib\httplib.py", line 856, in endheaders
self._send_output()
File "C:\Python25\lib\httplib.py", line 728, in _send_output
self.send(msg)
File "C:\Python25\lib\httplib.py", line 695, in send
self.connect()
File "C:\Python25\lib\httplib.py", line 679, in connect
raise socket.error, msg
IOError: [Errno socket error] (10060, 'Operation timed out')

I'm behind my company's firewall. Would that cause a problem? If it
does, How do I get around it?

See the documentation for urllib.urlopen:

"""
In a Windows environment, if no proxy environment variables are set,
proxy settings are obtained from the registry's Internet Settings
section.
"""
Remove Proxy configuration under IE and try again
(don't use Ie anymore ;0)