printing diamonds

[dragonwebz]

hey, I'm new here but heard a lot about some new stuff I could learn on here. However I'm kinda stuck on a program thats supposed to print a diamond depend what the user inputs as a width. Yes, I have seen this problem worked out in C++ before and I have spent a few hours trying to convert it into Python however I just can't seem to get the 'for' loop right. Any help on this part would be greatly appreciated.

[ghostdog74]

Post your code...

[kudos]

Do you need something like this?? this is more a hint than a complete solution

# print a diamond shape
# 
 
c = 5;
txt=""
k = 0
 
for j in range(12):
 txt=""
 for i in range(12):
  if (i<c-k) or (i>c+k):
   txt+=" "
  else:
   txt+="*"
 print txt  
 if(j>c):
  k-=1
 elif(k<c):
  k+=1
 else:
  k=c
 

-Kudos

hey, I'm new here but heard a lot about some new stuff I could learn on here. However I'm kinda stuck on a program thats supposed to print a diamond depend what the user inputs as a width. Yes, I have seen this problem worked out in C++ before and I have spent a few hours trying to convert it into Python however I just can't seem to get the 'for' loop right. Any help on this part would be greatly appreciated.