binding more than one attribute in a facntion

[linuxnow]

I want to have a bound method that "fixes" more than one parmeter of a
funtion. LEt me post an example.

def f(a, b, c):
return a + b + c

I can do:
fplus10 = f(10)
and then call f with 2 params and it works.

But, how can I fix 2 params:
fplus10plus20 = f(10,20)
ignores the second param.

fplus10plus20= fplus10(20)
does not work either.

Can anybody show what I'm doing wrong?

[bearophileHUGS]

li******@gmail.com:

def f(a, b, c): return a + b + c
I can do:
fplus10 = f(10)
and then call f with 2 params and it works.

If you call that f or that fplus10 with two parameters you obtain an
error in both cases. You have an error with the f(10) line too.

With Python 2.5 you can probably use the partial(), but for now you can
simply do:

def f(a, b, c):
return a + b + c
def fplus10(b, c):
return f(10, b, c)
def fplus10plus20(c):
return fplus10(20, c)

print f(10, 20, 30)
print fplus10(20, 30)
print fplus10plus20(30)

Bye,
bearophile

[Peter Otten]

li******@gmail.com wrote:

I want to have a bound method that "fixes" more than one parmeter of a
funtion. LEt me post an example.

def f(a, b, c):
return a + b + c

I can do:
fplus10 = f(10)
and then call f with 2 params and it works.

But, how can I fix 2 params:
fplus10plus20 = f(10,20)
ignores the second param.

fplus10plus20= fplus10(20)
does not work either.

Can anybody show what I'm doing wrong?

Bound methods are limited to one implicit parameter. What you need is
partial function application:

>>def f(a, b, c):

.... return a + b + c
....

>>def partial(f, *args):

.... def g(*more):
.... return f(*args+more)
.... return g
....

>>partial(f, 1, 2)(3)

6

>>partial(f, 1)(2, 3)

6

>>partial(f)(1, 2, 3)

6

See http://www.python.org/dev/peps/pep-0309/ for more.

Peter

[faulkner]

http://cheeseshop.python.org/pypi/functional

learn lisp/scheme!
http://cs.wwc.edu/KU/PR/Scheme.html
Peter Otten wrote:

li******@gmail.com wrote:

I want to have a bound method that "fixes" more than one parmeter of a
funtion. LEt me post an example.

def f(a, b, c):
return a + b + c

I can do:
fplus10 = f(10)
and then call f with 2 params and it works.

But, how can I fix 2 params:
fplus10plus20 = f(10,20)
ignores the second param.

fplus10plus20= fplus10(20)
does not work either.

Can anybody show what I'm doing wrong?

Bound methods are limited to one implicit parameter. What you need is
partial function application:

>def f(a, b, c):

... return a + b + c
...

>def partial(f, *args):

... def g(*more):
... return f(*args+more)
... return g
...

>partial(f, 1, 2)(3)

6

>partial(f, 1)(2, 3)

6

>partial(f)(1, 2, 3)

6

See http://www.python.org/dev/peps/pep-0309/ for more.

Peter

[linuxnow]

Peter Otten wrote:

li******@gmail.com wrote:

Bound methods are limited to one implicit parameter. What you need is
partial function application:

>def f(a, b, c):

... return a + b + c
...

>def partial(f, *args):

... def g(*more):
... return f(*args+more)
... return g
...

>partial(f, 1, 2)(3)

6

>partial(f, 1)(2, 3)

6

>partial(f)(1, 2, 3)

6

See http://www.python.org/dev/peps/pep-0309/ for more.

Thanks, this explanation is great. Nice to see also that python 2.5
will have it,