Module for creating a screenshot of a web page given a URL?

[dananrg]

Is there a Python module that, given a URL, will grab a screenshot of
the web page it goes to? I'd like to be able to feed such a module a
list of URLs from a file.

Thanks very much.

[Rune Strand]

da*****@yahoo.com wrote:

Is there a Python module that, given a URL, will grab a screenshot of
the web page it goes to? I'd like to be able to feed such a module a
list of URLs from a file.

Thanks very much.

Not as I know of, but it's easy to write

Something like this quasi-code:

import time,webbrowser
from PIL import ImageGrab

list_of_urls = [''http://www.google.com', 'http://www.egg.net']

for url in list_of_urls:
webbrowser.open(url)
time.sleep(5) # wait for it to load
screen = ImageGrab.grab(coords etc)
screen.save(some_name_in_some_path)

Untestetd, but I'm pretty sure something like this will do.
If you need more control, and on windows, try pywinauto

[dananrg]

Untestetd, but I'm pretty sure something like this will do.

If you need more control, and on windows, try pywinauto

I do need it to run on Windows. I'll check out pywinauto. Thanks.

[John J. Lee]

da*****@yahoo.com writes:

Untestetd, but I'm pretty sure something like this will do.
If you need more control, and on windows, try pywinauto

I do need it to run on Windows. I'll check out pywinauto. Thanks.

Note he didn't say you *need* pywinauto to run on Windows.
John

[chemila66]

John J. Lee wrote:

>
da*****@yahoo.com writes:

Untestetd, but I'm pretty sure something like this will do.
If you need more control, and on windows, try pywinauto

I do need it to run on Windows. I'll check out pywinauto. Thanks.

Note he didn't say you *need* pywinauto to run on Windows.
John
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Is there anyway to do the same job in linux?
The ImageGrab doesn't support for linux system.

If anyone knows that, please, reply me. Thanks a lot.
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