I have the following code which takes a list of urls
"http://google.com", without the quotes ofcourse, and then saves there
source code as a text file. I wan to alter the code so that for the
list of URLs an html file is saved.
-----begin-----
import urllib
urlfile = open(r'c:\temp\url.txt', 'r')
for lines in urlfile:
try:
outfilename = lines.replace('/', '-')
urllib.urlretrieve(lines.strip('/n'), 'c:\\temp\\' \
+ outfilename.strip('\n')[7:] + '.txt')
except:
pass
-----end-----
7  1474 
Then just write HTML around your list. I would guess
you want them inside a table. Just write appropriate
HTML tags before/after the urls. If you want the URLs
to be clickable make them in into <a href>url</a> lines.
-Larry Bates
Shani wrote: I have the following code which takes a list of urls
"http://google.com", without the quotes ofcourse, and then saves there
source code as a text file. I wan to alter the code so that for the
list of URLs an html file is saved.
-----begin-----
import urllib
urlfile = open(r'c:\temp\url.txt', 'r')
for lines in urlfile:
try:
outfilename = lines.replace('/', '-')
urllib.urlretrieve(lines.strip('/n'), 'c:\\temp\\' \
+ outfilename.strip('\n')[7:] + '.txt')
except:
pass
-----end-----
"Shani" <Sh******@gmail.com> wrote in message
news:11**********************@j55g2000cwa.googlegr oups.com... I have the following code which takes a list of urls
"http://google.com", without the quotes ofcourse, and then saves there
source code as a text file. I wan to alter the code so that for the
list of URLs an html file is saved.
-----begin-----
import urllib
urlfile = open(r'c:\temp\url.txt', 'r')
for lines in urlfile:
try:
outfilename = lines.replace('/', '-')
urllib.urlretrieve(lines.strip('/n'), 'c:\\temp\\' \
+ outfilename.strip('\n')[7:] + '.txt')
except:
pass
-----end-----
Is this what you mean?
-----begin-----
import urllib
urlfile = open(r'c:\temp\url.txt', 'r')
for lines in urlfile:
try:
outfilename = lines.replace('/', '-')
urllib.urlretrieve(lines.strip('/n'), 'c:\\temp\\' \
+ outfilename.strip('\n')[7:] + '.html')
except:
pass
-----end-----
Louis
"Shani" <Sh******@gmail.com> wrote in message
news:11**********************@j55g2000cwa.googlegr oups.com... I have the following code which takes a list of urls
"http://google.com", without the quotes ofcourse, and then saves there
source code as a text file. I wan to alter the code so that for the
list of URLs an html file is saved.
-----begin-----
import urllib
urlfile = open(r'c:\temp\url.txt', 'r')
for lines in urlfile:
try:
outfilename = lines.replace('/', '-')
urllib.urlretrieve(lines.strip('/n'), 'c:\\temp\\' \
+ outfilename.strip('\n')[7:] + '.txt')
except:
pass
-----end-----
Or is this what you mean?
-----begin-----
import urllib
urlfile = open('c:\\temp\\url.txt', 'r')
newurlfile = open('c:\\temp\\newurls.html', 'w')
newurlfile.write('<html> \n<body>\n')
for lines in urlfile:
try:
if lines == '\n':
pass
else:
lines = '<a href="' + lines.strip() +'">'\
+ lines.strip() + '</a>' + '<br>\n'
newurlfile.write(lines)
except:
pass
newurlfile.write('</body> \n</html>')
urlfile.close()
newurlfile.close()
-----end-----
Louis
"3c273" <no****@nospam.com> wrote in message
news:e6*********@enews2.newsguy.com... Or is this what you mean?
-----begin-----
import urllib
urlfile = open('c:\\temp\\url.txt', 'r')
newurlfile = open('c:\\temp\\newurls.html', 'w')
newurlfile.write('<html> \n<body>\n')
for lines in urlfile:
try:
if lines == '\n':
pass
else:
lines = '<a href="' + lines.strip() +'">'\
+ lines.strip() + '</a>' + '<br>\n'
newurlfile.write(lines)
except:
pass
newurlfile.write('</body> \n</html>')
urlfile.close()
newurlfile.close()
-----end-----
Louis
Oops, I guess we don't need "import urllib" anymore.
Louis
Shani wrote: I have the following code which takes a list of urls
"http://google.com", without the quotes ofcourse, and then saves there
source code as a text file. I wan to alter the code so that for the
list of URLs an html file is saved.
What you write in a text file is up to you - and AFAICT, HTML is still
a text format.
--
bruno desthuilliers
python -c "print '@'.join(['.'.join([w[::-1] for w in p.split('.')]) for
p in 'o****@xiludom.gro'.split('@')])"
> Is this what you mean?
-----begin-----
import urllib
urlfile = open(r'c:\temp\url.txt', 'r')
for lines in urlfile:
try:
outfilename = lines.replace('/', '-')
urllib.urlretrieve(lines.strip('/n'), 'c:\\temp\\' \
+ outfilename.strip('\n')[7:] + '.html')
except:
pass
-----end-----
[laughs] I suspect the urlretrieve line should contain
"strip('\n')" instead of "strip('/n')", but otherwise, the
original code looked pretty kosher. I'm not sure what the odd
slicing is for, but I'll presume the OP knows what they're doing.
While not a python solution, the standard *nix tool would be
either wget or curl:
bash> wget -i listofurls.txt
which is freely available with the Cygwin suite of GNU tools for
Win32 platforms.
-tkc
Tim Chase <ti*@thechases.com> wrote: [ ... ]
urllib.urlretrieve(lines.strip('/n'), 'c:\\temp\\' \
+ outfilename.strip('\n')[7:] + '.html')
[ ... ] I'm not sure what the odd
slicing is for, but I'll presume the OP knows what they're doing.
It's taking the "http://" off the front of the URL. len("http://")
7
--
\S -- si***@chiark.greenend.org.uk -- http://www.chaos.org.uk/~sion/
___ | "Frankly I have no feelings towards penguins one way or the other"
\X/ | -- Arthur C. Clarke
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