P: n/a

I wrote the following code to concatenate every 2 keys of a dictionary and
their corresponding values.
e.g if i have tiDict1 = tiDict1 = {'a':[1,2],'b':[3,4,5]} i should get
tiDict2={'ab':[1,2][3,4,5]} and similarly for dicts with larger no. of
features.
Now i want to check each pair to see if they are connected...element of
this pair will be one from the first list and one from the second....e.g
for 'ab' i want to check if 1 and 3 are connected,then 1 and 4,then 1 and
5,then 2 and 3,then 2 and 4,then 2 and 5.
The information of this connected thing is in a text file as follows:
1,'a',2,'b'
3,'a',5,'a'
3,'a',6,'a'
3,'a',7,'b'
8,'a',7,'b'
..
..
This means 1(type 'a') and 2(type 'b') are connected,3 and 5 are connected
and so on.
I am not able to figure out how to do this.Any pointers would be helpful
Here is the code i have written till now: 
def genTI(tiDict):

tiDict1 = {}

tiList = [tiDict1.keys(),tiDict1.values()]

length =len(tiDict1.keys())1

for i in range(0,length,1):

for j in range(0,length,1):

for k in range(1,length+1,1):

if j+k <= length:

key = tiList[i][j] + tiList[i][j+k]

value = [tiList[i+1][j],tiList[i+1][j+k]]

tiDict2[key] = value

continue

continue

continue

return tiDict2

Thanks in advance,
girish  
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P: n/a

Girish Sahani wrote: I wrote the following code to concatenate every 2 keys of a dictionary and their corresponding values. e.g if i have tiDict1 = tiDict1 = {'a':[1,2],'b':[3,4,5]} i should get tiDict2={'ab':[1,2][3,4,5]} and similarly for dicts with larger no. of features. Now i want to check each pair to see if they are connected...element of this pair will be one from the first list and one from the second....e.g for 'ab' i want to check if 1 and 3 are connected,then 1 and 4,then 1 and 5,then 2 and 3,then 2 and 4,then 2 and 5. The information of this connected thing is in a text file as follows: 1,'a',2,'b' 3,'a',5,'a' 3,'a',6,'a' 3,'a',7,'b' 8,'a',7,'b' . . This means 1(type 'a') and 2(type 'b') are connected,3 and 5 are connected and so on. I am not able to figure out how to do this.Any pointers would be helpful
Girish
It seems you want the Cartesian product of every pair of lists in the
dictionary, including the product of lists with themselves (but you
don't say why ;)).
I'm not sure the following is exactly what you want or if it is very
efficient, but maybe it will start you off. It uses a function
'xcombine' taken from a recipe in the ASPN cookbook by David
Klaffenbach (2004).
(It should give every possibility, which you then check in your file)
Gerard

def nkRange(n,k):
m = n  k + 1
indexer = range(0, k)
vector = range(1, k+1)
last = range(m, n+1)
yield vector
while vector != last:
high_value = 1
high_index = 1
for i in indexer:
val = vector[i]
if val > high_value and val < m + i:
high_value = val
high_index = i
for j in range(k  high_index):
vector[j+high_index] = high_value + j + 1
yield vector
def kSubsets( alist, k ):
n = len(alist)
for vector in nkRange(n, k):
ret = []
for i in vector:
ret.append( alist[i1] )
yield ret
data = { 'a': [1,2], 'b': [3,4,5], 'c': [1,4,7] }
pairs = list( kSubsets(data.keys(),2) ) + [ [k,k] for k in
data.iterkeys() ]
print pairs
for s in pairs:
for t in xcombine( data[s[0]], data[s[1]] ):
print "%s,'%s',%s,'%s'" % ( t[0], s[0], t[1], s[1] )

1,'a',1,'c'
1,'a',4,'c'
1,'a',7,'c'
2,'a',1,'c'
2,'a',4,'c'
2,'a',7,'c'
1,'a',3,'b'
1,'a',4,'b'
1,'a',5,'b'
2,'a',3,'b'
2,'a',4,'b'
2,'a',5,'b'
1,'c',3,'b'
1,'c',4,'b'
1,'c',5,'b'
4,'c',3,'b'
4,'c',4,'b'
4,'c',5,'b'
7,'c',3,'b'
7,'c',4,'b'
7,'c',5,'b'
1,'a',1,'a'
1,'a',2,'a'
2,'a',1,'a'
2,'a',2,'a'
1,'c',1,'c'
1,'c',4,'c'
1,'c',7,'c'
4,'c',1,'c'
4,'c',4,'c'
4,'c',7,'c'
7,'c',1,'c'
7,'c',4,'c'
7,'c',7,'c'
3,'b',3,'b'
3,'b',4,'b'
3,'b',5,'b'
4,'b',3,'b'
4,'b',4,'b'
4,'b',5,'b'
5,'b',3,'b'
5,'b',4,'b'
5,'b',5,'b'  
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Gerard Flanagan wrote: Girish Sahani wrote: I wrote the following code to concatenate every 2 keys of a dictionary and their corresponding values. e.g if i have tiDict1 = tiDict1 = {'a':[1,2],'b':[3,4,5]} i should get tiDict2={'ab':[1,2][3,4,5]} and similarly for dicts with larger no. of features. Now i want to check each pair to see if they are connected...element of this pair will be one from the first list and one from the second....e.g for 'ab' i want to check if 1 and 3 are connected,then 1 and 4,then 1 and 5,then 2 and 3,then 2 and 4,then 2 and 5. The information of this connected thing is in a text file as follows: 1,'a',2,'b' 3,'a',5,'a' 3,'a',6,'a' 3,'a',7,'b' 8,'a',7,'b' . . This means 1(type 'a') and 2(type 'b') are connected,3 and 5 are connected and so on. I am not able to figure out how to do this.Any pointers would be helpful
Girish
It seems you want the Cartesian product of every pair of lists in the dictionary, including the product of lists with themselves (but you don't say why ;)).
I'm not sure the following is exactly what you want or if it is very efficient, but maybe it will start you off. It uses a function 'xcombine' taken from a recipe in the ASPN cookbook by David Klaffenbach (2004). http://aspn.activestate.com/ASPN/Coo.../Recipe/302478  
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I have a text file in the following format:
1,'a',2,'b'
3,'a',5,'c'
3,'a',6,'c'
3,'a',7,'b'
8,'a',7,'b'
..
..
..
Now i need to generate 2 things by reading the file:
1) A dictionary with the numbers as keys and the letters as values.
e.g the above would give me a dictionary like
{1:'a', 2:'b', 3:'a', 5:'c', 6:'c' ........}
2) A list containing pairs of numbers from each line.
The above formmat would give me the list as
[[1,2],[3,5],[3,6][3,7][8,7]......]
I wrote the following codes for both of these but the problem is that
lines returns a list like ["1,'a',2,'b'","3,'a',5,'c","3,'a',6,'c'".....]
Now due to the "" around each line,it is treated like one object
and i cannot access the elements of a line. 
#code to generate the dictionary

def get_colocations(filename):

lines = open(filename).read().split("\n")

colocnDict = {}

i = 0

for line in lines:

if i <= 2:

colocnDict[line[i]] = line[i+1]

i+=2

continue

return colocnDict


def genPairs(filename):

lines = open(filename).read().split("\n")

pairList = []

for line in lines:

pair = [line[0],line[2]]

pairList.append(pair)

i+=2

continue

return pairList

Please help :((  
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Girish Sahani wrote: 1) A dictionary with the numbers as keys and the letters as values. e.g the above would give me a dictionary like {1:'a', 2:'b', 3:'a', 5:'c', 6:'c' ........}
def get_dict( f ) :
out = {}
for line in file(f) :
n1,s1,n2,s2 = line.split(',')
out.update( { int(n1):s1[1], int(n2):s2[1] } )
return out
2) A list containing pairs of numbers from each line. The above formmat would give me the list as [[1,2],[3,5],[3,6][3,7][8,7]......]
def get_pairs( f ) :
out = []
for line in file(f) :
n1,_,n2,_ = line.split(',')
out.append( [int(n1),int(n2)] )
return out
Regards
Sreeram
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Version: GnuPG v1.4.2.2 (MingW32)
Comment: Using GnuPG with Mozilla  http://enigmail.mozdev.org
iD8DBQFEhQdNrgn0plK5qqURAiVkAJ9Rr0XRRhofIP4Z2eYF1n FvvHTCUgCgmMkM
6U9ieDTmvItGbW8QKUCWrFo=
=wwVC
END PGP SIGNATURE  
P: n/a

On 6/06/2006 2:10 PM, Girish Sahani wrote: I have a text file in the following format:
1,'a',2,'b' 3,'a',5,'c' 3,'a',6,'c' 3,'a',7,'b' 8,'a',7,'b'
Check out the csv module.
. . . Now i need to generate 2 things by reading the file: 1) A dictionary with the numbers as keys and the letters as values. e.g the above would give me a dictionary like {1:'a', 2:'b', 3:'a', 5:'c', 6:'c' ........} 2) A list containing pairs of numbers from each line. The above formmat would give me the list as [[1,2],[3,5],[3,6][3,7][8,7]......]
I wrote the following codes for both of these but the problem is that lines returns a list like ["1,'a',2,'b'","3,'a',5,'c","3,'a',6,'c'".....] Now due to the "" around each line,it is treated like one object and i cannot access the elements of a line.
You managed to split the file contents into lines using
lines = open(filename).read().split("\n")
Same principle applies to each line:
>>> lines = ["1,'a',2,'b'","3,'a',5,'c","3,'a',6,'c'"]
>>> lines[0].split(',')
['1', "'a'", '2', "'b'"]
>>> lines[1].split(',')
['3', "'a'", '5', "'c"]
>>>  #code to generate the dictionary
 def get_colocations(filename):
 lines = open(filename).read().split("\n")
 colocnDict = {}
 i = 0
 for line in lines:
 if i <= 2:
 colocnDict[line[i]] = line[i+1]
 i+=2
 continue
 return colocnDict
The return is indented too far; would return after 1st line.  def genPairs(filename):
 lines = open(filename).read().split("\n")
 pairList = []
 for line in lines:
 pair = [line[0],line[2]]
 pairList.append(pair)
 i+=2


i is not defined. This would cause an exception. Please *always* post

the code that you actually ran.

 continue
 return pairList


dedented too far!!


Please help :((
def get_both(filename):
lines = open(filename).read().split("\n")
colocnDict = {}
pairList = []
for line in lines:
n1, b1, n2, b2 = line.split(",")
n1 = int(n1)
n2 = int(n2)
a1 = b1.strip("'")
a2 = b2.strip("'")
colocnDict[n1] = a1
colocnDict[n2] = a2
pairList.append([n1, n2])
return colocnDict, pairList
def get_both_csv(filename):
import csv
reader = csv.reader(open(filename, "rb"), quotechar="'")
colocnDict = {}
pairList = []
for n1, a1, n2, a2 in reader:
n1 = int(n1)
n2 = int(n2)
colocnDict[n1] = a1
colocnDict[n2] = a2
pairList.append([n1, n2])
return colocnDict, pairList
HTH,
John  
P: n/a

Girish Sahani wrote: Gerard Flanagan wrote: Girish Sahani wrote: > I wrote the following code to concatenate every 2 keys of a dictionary and > their corresponding values. > e.g if i have tiDict1 = tiDict1 = {'a':[1,2],'b':[3,4,5]} i should get > tiDict2={'ab':[1,2][3,4,5]} and similarly for dicts with larger no. of > features. > Now i want to check each pair to see if they are connected...element of > this pair will be one from the first list and one from the second....e.g > for 'ab' i want to check if 1 and 3 are connected,then 1 and 4,then 1 and > 5,then 2 and 3,then 2 and 4,then 2 and 5. > The information of this connected thing is in a text file as follows: > 1,'a',2,'b' > 3,'a',5,'a' > 3,'a',6,'a' > 3,'a',7,'b' > 8,'a',7,'b' > . > . > This means 1(type 'a') and 2(type 'b') are connected,3 and 5 are connected > and so on. > I am not able to figure out how to do this.Any pointers would be helpful
Girish
It seems you want the Cartesian product of every pair of lists in the dictionary, including the product of lists with themselves (but you don't say why ;)).
I'm not sure the following is exactly what you want or if it is very efficient, but maybe it will start you off. It uses a function 'xcombine' taken from a recipe in the ASPN cookbook by David Klaffenbach (2004).
http://aspn.activestate.com/ASPN/Coo.../Recipe/302478
 http://mail.python.org/mailman/listinfo/pythonlist
Thanks a lot Gerard and Roberto.but i think i should explain the exact thing with an example. Roberto what i have right now is concatenating the keys and the corresponding values: e.g {'a':[1,2],'b':[3,4,5],'c':[6,7]} should give me {'ab':[1,2][3,4,5] 'ac':[1,2][6,7] 'bc':[3,4,5][6,7]} The order doesnt matter here.It could be 'ac' followed by 'bc' and 'ac'. Also order doesnt matter in a string:the pair 'ab':[1,2][3,4,5] is same as 'ba':[3,4,5][1,2]. This representation means 'a' corresponds to the list [1,2] and 'b' corresponds to the list [3,4,5]. Now, for each keyvalue pair,e.g for 'ab' i must check each feature in the list of 'a' i.e. [1,2] with each feature in list of 'b' i.e. [3,4,5].So I want to take cartesian product of ONLY the 2 lists [1,2] and [3,4,5]. Finally i want to check each pair if it is present in the file,whose format i had specified. The code Gerard has specified takes cartesian products of every 2 lists.
Hi Garish,
it's better to reply to the Group.
Now, for each keyvalue pair,e.g for 'ab' i must check each feature in the list of 'a' i.e. [1,2] with each feature in list of 'b' i.e. [3,4,5].So I want to take cartesian product of ONLY the 2 lists [1,2] and [3,4,5].
I'm confused. You say *for each* keyvalue pair, and you wrote above
that the keys were the 'concatenation' of "every 2 keys of a
dictionary".
Sorry, too early for me. Maybe if you list every case you want, given
the example data.
All the best.
Gerard  
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Really sorry for that indentation thing :)
I tried out the code you have given, and also the one sreeram had written.
In all of these,i get the same error of this type:
Error i get in Sreeram's code is:
n1,_,n2,_ = line.split(',')
ValueError: need more than 1 value to unpack
And error i get in your code is:
for n1, a1, n2, a2 in reader:
ValueError: need more than 0 values to unpack
Any ideas why this is happening?
Thanks a lot,
girish  
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On 6/06/2006 4:15 PM, Girish Sahani wrote: Really sorry for that indentation thing :) I tried out the code you have given, and also the one sreeram had written. In all of these,i get the same error of this type: Error i get in Sreeram's code is: n1,_,n2,_ = line.split(',') ValueError: need more than 1 value to unpack
And error i get in your code is: for n1, a1, n2, a2 in reader: ValueError: need more than 0 values to unpack
Any ideas why this is happening?
In the case of my code, this is consistent with the line being empty,
probably the last line. As my mentor Bruno D. would say, your test data
does not match your spec :) Which do you want to change, the spec or
the data?
You can change my csvreading code to detect dodgy data like this (for
example):
for row in reader:
if not row:
continue # ignore empty lines, wherever they appear
if len(row) != 4:
raise ValueError("Malformed row %r" % row)
n1, a1, n2, a2 = row
In the case of Sreeram's code, perhaps you could try inserting
print "line = ", repr(line)
before the statement that is causing the error. Thanks a lot, girish  
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Girish> I have a text file in the following format:
Girish> 1,'a',2,'b'
Girish> 3,'a',5,'c'
Girish> 3,'a',6,'c'
Girish> 3,'a',7,'b'
Girish> 8,'a',7,'b'
Girish> .
Girish> .
Girish> .
Girish> Now i need to generate 2 things by reading the file:
Girish> 1) A dictionary with the numbers as keys and the letters as values.
Girish> e.g the above would give me a dictionary like
Girish> {1:'a', 2:'b', 3:'a', 5:'c', 6:'c' ........}
Girish> 2) A list containing pairs of numbers from each line.
Girish> The above formmat would give me the list as
Girish> [[1,2],[3,5],[3,6][3,7][8,7]......]
Running this:
open("some.text.file", "w").write("""\
1,'a',2,'b'
3,'a',5,'c'
3,'a',6,'c'
3,'a',7,'b'
8,'a',7,'b'
""")
import csv
class dialect(csv.excel):
quotechar = "'"
reader = csv.reader(open("some.text.file", "rb"), dialect=dialect)
mydict = {}
mylist = []
for row in reader:
numbers = [int(n) for n in row[::2]]
letters = row[1::2]
mydict.update(dict(zip(numbers, letters)))
mylist.append(numbers)
print mydict
print mylist
import os
os.unlink("some.text.file")
displays this:
{1: 'a', 2: 'b', 3: 'a', 5: 'c', 6: 'c', 7: 'b', 8: 'a'}
[[1, 2], [3, 5], [3, 6], [3, 7], [8, 7]]
That seems to be approximately what you're looking for.
Skip  
P: n/a

> On 6/06/2006 4:15 PM, Girish Sahani wrote: Really sorry for that indentation thing :) I tried out the code you have given, and also the one sreeram had written. In all of these,i get the same error of this type: Error i get in Sreeram's code is: n1,_,n2,_ = line.split(',') ValueError: need more than 1 value to unpack
And error i get in your code is: for n1, a1, n2, a2 in reader: ValueError: need more than 0 values to unpack
Any ideas why this is happening? In the case of my code, this is consistent with the line being empty, probably the last line. As my mentor Bruno D. would say, your test data does not match your spec :) Which do you want to change, the spec or the data?
Thanks John, i just changed my Data file so as not to contain any empty
lines, i guess that was the easier solution ;) You can change my csvreading code to detect dodgy data like this (for example):
for row in reader: if not row: continue # ignore empty lines, wherever they appear if len(row) != 4: raise ValueError("Malformed row %r" % row) n1, a1, n2, a2 = row
In the case of Sreeram's code, perhaps you could try inserting print "line = ", repr(line) before the statement that is causing the error.
Thanks a lot, girish
 http://mail.python.org/mailman/listinfo/pythonlist  
P: n/a

Girish said, through Gerard's forwarded message: Thanks a lot Gerard and Roberto.but i think i should explain the exact thing with an example. Roberto what i have right now is concatenating the keys and the corresponding values: e.g {'a':[1,2],'b':[3,4,5],'c':[6,7]} should give me {'ab':[1,2][3,4,5] 'ac':[1,2][6,7] 'bc':[3,4,5][6,7]} The order doesnt matter here.It could be 'ac' followed by 'bc' and 'ac'. Also order doesnt matter in a string:the pair 'ab':[1,2][3,4,5] is same as 'ba':[3,4,5][1,2]. This representation means 'a' corresponds to the list [1,2] and 'b' corresponds to the list [3,4,5].
The problem if that the two lists aren't distinguishable when
concatenated, so what you get is [1, 2, 3, 4, 5]. You have to pack
both lists in a tuple: {'ab': ([1, 2], [3, 4, 5]), ...} d = {'a':[1, 2], 'b':[3, 4, 5], 'c':[6, 7]} d2 = dict(((i + j), (d[i], d[j])) for i in d for j in d if i < j) d2
{'ac': ([1, 2], [6, 7]), 'ab': ([1, 2], [3, 4, 5]), 'bc': ([3, 4, 5], [6, 7])} Now, for each keyvalue pair,e.g for 'ab' i must check each feature in the list of 'a' i.e. [1,2] with each feature in list of 'b' i.e. [3,4,5].So I want to take cartesian product of ONLY the 2 lists [1,2] and [3,4,5].
You can do this without creating an additional dictionary:
d = {'a':[1, 2], 'b':[3, 4, 5], 'c':[6, 7]} pairs = [i + j for i in d for j in d if i < j] for i, j in pairs:
.... cartesian_product = [(x, y) for x in d[i] for y in d[j]]
.... print i + j, cartesian_product
....
ac [(1, 6), (1, 7), (2, 6), (2, 7)]
ab [(1, 3), (1, 4), (1, 5), (2, 3), (2, 4), (2, 5)]
bc [(3, 6), (3, 7), (4, 6), (4, 7), (5, 6), (5, 7)]
You can do whatever you want with this cartesian product inside the loop.
Finally i want to check each pair if it is present in the file,whose format i had specified.
I don't understand the semantics of the file format, so I leave this
as an exercise to the reader :)
Best regards.

Roberto Bonvallet   This discussion thread is closed Replies have been disabled for this discussion.   Question stats  viewed: 5105
 replies: 11
 date asked: Jun 5 '06
